#Eigenvalue of A^(tr) * A and A * A^(tr)

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silver garnet
devout anvilBOT
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silver garnet
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Now, apparently this doesn't hold if lambda = 0. But couldn't I just argue exactly like in the proof above? Where exactly does it fail

cobalt minnow
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The only good explanation I found for why the != 0 condition is requires is because you're proving the lambda-eigenspaces of $AA^T$ and $A^TA$ are isomorphic, and the isomorphism used invokes 1/sqrt(lambda)

ivory ruinBOT
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Omegabet_

cobalt minnow
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(there's probably also some connection to the SVD of A that I'm neglecting/forgetting)

hoary wadiBOT
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@silver garnet has given 1 rep to @cobalt minnow

silver garnet
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+close