Basic geometry

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[rotund sedge]

as angle anm= angle amn

it is given in diagram

x

oh

cd would be parallel to a right

since it is a regular polygon

wait, let me check

[mighty salmon]

Because NMDC is a square with CD parallel to MN and ABCDE is regular, meaning A is at the midpoint of CD, which is also the midpoint of MN.

In any regular n-gon where n is odd, the bisector of any angle is always the perpendicular bisector of the opposite side.

And vice versa.

[mighty salmon]

...there's no such thing as parallel to a point.

[shut iron]

@merry sky has given 1 rep to @mighty salmon

[mighty salmon]

I mean, if you like, but considering you came here asking about it, I'd assumed you'd already tried and failed.

[tight hornet]

its either isoceles or equilateral

actually its more likely isoceles

[flat thunder]

it is isosceles

i believe techie has already suggested dropping a perpendicular from A to CD

[tight hornet]

yeah

it is

mhm\

[flat thunder]

this bisects CD; it will also bisect MN

[tight hornet]

actually we could solve angle NAM and BAE

since its a regular polygon

BAE is 108

[flat thunder]

unnecessary

[tight hornet]

meaning that 2y + 180 - 2x = 108

[tight hornet]

why

[flat thunder]

yes

[flat thunder]

<NAM is unnecessary

<BAE is enough

[tight hornet]

fine

[shut iron]

@merry sky has given 1 rep to @mighty salmon