#homework help please
night compass
river micaBOT
- Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close - Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
night compass
@torpid palm here love, you can explain yourself and get hell here like you would in DM’s or a channel
cerulean basalt
What needs to be done? Solving for x in terms of a?
night compass
What needs to be done? Solving for x in terms of a?
Man can’t access his own channel
Let me fix so he can tell lmao
cerulean basalt
Oh. Hm, that's odd.
ebon otter
wait this is calculus? seems like its not
ebon otter
(n^2)^2 = n^2*2
ax^2 = a^2 * x^2
is that right?
ye i think so
and cant we change the square root to power of 1/2
upbeat ledgeBOT
ゴゴcurry supplierゴゴ(art arc)
ebon otter
BRUH
this isnt working
sorry this is not easy
mb
can i simply do the quadratic equation to this?
cerulean basalt
Let u = √(4x - x^2).
u^4 - 32u = a^2 - 14a
u^4 - 32u does have a global minimum at (2, -48). So:
u^4 - 32u + 48 = a^2 - 14a + 48
So, if a^2 - 14a + 48 = 0, so if a = 6 or a = 8, the only real root is u = 2, and it's easy from here. Not sure otherwise.
Again, what's the question in this problem?
ebon otter
idk
its probably to find x in terms of a
or x and a seperately
or to maybe simplify this equation
cerulean basalt
Well... I mean, I think the general solution will require usage of the quartic formula, which is a huge pain.