Using Functions to Model Real Change

[severe dew]

I need help to learn this material.

[clever olive]

1. Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
2. Wait patiently for a helper to come along.
3. Once someone helps you, say thank you and close the thread with:

   +close
   

4. Feel free to nominate the person for helper of the week in #helper-nominations
5. Do not ping the mods, unless someone is breaking the rules.
6. If you're happy with the help you got here, and the server overall, you can contribute financially as well:

[past axle]

Find the intercepts and use intercept form

[severe dew]

A: y = 2x + 3?

[past axle]

Yea

[severe dew]

would that be the function?

[past axle]

Yea

That's a function in X

So y=f(X)

[severe dew]

So, f(x)=2x+3 would be my answer.

for a.

[past axle]

For the first one, yea

B is a bit simpler

And easy to get done with

[severe dew]

Would it be g(x)=2x-6 or f(x)=2x-6

[past axle]

F

F(X)

[severe dew]

Why would the F change to G?

[past axle]

It doesn't

[severe dew]

I mean in general.

[past axle]

It can though, doesn't make much diff

[past axle]

Cuz f(X) is taken

You can still use f(x) since it acts as y axis

[severe dew]

Ok, I understand now.

[past axle]

Yea

C is quite simple as well

Just visualise it

[severe dew]

Do I just type "it has to become a reflection?"

[past axle]

It's not a reflection

Youll have to rotate it about the point of intersection

[severe dew]

"It would have to rotate counter-clockwise by 1.5 units?"

[past axle]

Btw

B is -2x-6

Since the slope is negative

[severe dew]

Thank you for spotting that out.

[past axle]

Units? Mention in radians or degrees

[past axle]

Yea no worries

[severe dew]

1. I don't know what a radian is. 2. I have not learned how to use degrees in graphs.

[past axle]

Alr then

You'll get it by reflecting line A on the line perpendicular to X axis and passing through the point of intersection

[severe dew]

I'm so sorry, but I do not understand what you are trying to convey to me.

[past axle]

Line a is red line

B is blue like

B is achieved by reflecting a on green line

[severe dew]

How does this help me achieve my answer in question C.

[past axle]

Alr type this

"A can be converted into B by reflecting a on a like perpendicular to the horizontal X axis and the line has to pass through the point of intersection of line A and line B namely
(-9/4, -3/2)

Thank me later

[severe dew]

I'm very sorry, but I cannot thank you. I am grateful you have answered my last question but, I have learned literally nothing.

Thank you, for you time though.

+close