#reimann's theorem on absolutely convergent series
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You can start doing the positive case ie $(a_n)$ is a positive sequence in that case $\sum_{n=0}^{\infty} a_n=\sum_{n \in \mathbb{N}} a_n$ and if $\sigma$ is a bijection from $\mathbb{N}$ to itself then $\sum_{n \in \mathbb{N}} a_{\sigma(n)}=\sum_{n \in \sigma \left(\mathbb{N}\right)} a_n$
Rotor
The first one is also true for any summable family ie if $(b_n){n \in \mathbb{N}}$ is summable then $\sum{n=0}^{\infty} b_n=\sum_{n \in \mathbb{N}} b_n$
Rotor
Summability being equivalent to absolute convergence of the series for families indexed by $\mathbb{N}$ it follows
Rotor
Hmmm you know what while what I said is true it feels a bit cheap to directly use a property on summable families so I have another proof I think I can propose that uses the same underlying ideas but more rigorously
I won’t give the whole proof just the ideas
Like I said start in the case that (a_n) is a positive sequence
In that case you can consider $S_n=\sum_{k=0}^{n} a_k$ and $\Sigma_n=\sum_{k=0}^{n} a_{\sigma(k)}$
Rotor
($\sigma$ here is like before a bijection from $\mathbb{N}$ to itself)
Rotor
$(S_n){n \in \mathbb{N}}$ and $(\Sigma_n){n \in \mathbb{N}}$ are both increasing sequences ($(a_n)$ having positive values)
Rotor
In that case we have $\underset{n \to \infty}{lim} S_n=Sup{S_n, n \in \mathbb{N}}$
Rotor
Likewise $\underset{n \to \infty}{lim} \Sigma_n=Sup{\Sigma_n, n \in \mathbb{N}}$
Rotor
Calling $L$ and $L’$ their respective limits you can prove that $\forall n \in \mathbb{N}, S_n \le L’$ and that $\forall n \in \mathbb{N}, \Sigma_n \le L$
Rotor
(Hint: $\sum_{k=0}^{n} a_{\sigma(k)}=\sum_{k \in {1,…,n}}a_{\sigma(k)}$)
Rotor
via a change of variables it’s equal to $\sum_{k \in \sigma({1,…,n})} a_k$
Rotor
Sorry for yapping so long I hope it isn’t too confusing
This proves that L=L’
Which concludes the positive case
I’ll stop typing for now if you need help with the general case tell me (think of how you did to prove that absolute convergence => convergence)
with (a_n+) and (a_n-)
@mighty shard
sum a_n converges absolutely, hence its remainder converges to zero, pick large enough N such that the remainder is smaller than epsilon / 2
Then apply triangle inequality
@mighty shard