#suvat

41 messages · Page 1 of 1 (latest)

neon patio
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Does anyone know what I’ve done wrong? My answer isn’t in the options

thorny glacierBOT
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amber jackal
neon patio
amber jackal
neon patio
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y=((v2-v1)/(t2-t1))x + c

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should i find c aswell?

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c= v2-(((v2-v1)/(t2-t1))t2

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y=((v2-v1)/(t2-t1))x + v2-(((v2-v1)/(t2-t1))t2 that looks complicated

amber jackal
# neon patio y=((v2-v1)/(t2-t1))x + c

Our variables are t and v, not x and y. So:
v = v1 + (v2 - v1)(t - t1)/(t2 - t1)
Now, we want v = 0. So:
v1 + (v2 - v1)(t - t1)/(t2 - t1) = 0
Solve this for t.

neon patio
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t=(t2v1-t1v2)/(v1-v2)

amber jackal
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Right, nice!

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So, now you can substitute the values.

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Note that you can divide the numerator and denominator by v1 v2, obtaining an even nicer expression:
t = (t2/v2 - t1/v1)/(1/v2 - 1/v1) = Δ(t/v)/Δ(1/v)

neon patio
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im not sure why but im still not getting an answer

amber jackal
neon patio
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44..

amber jackal
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No, that's not correct. Can you show your calculation?

neon patio
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I just tried it again i got 357/3

amber jackal
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No, still not correct.

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Again, can you show how you're calculating it?

neon patio
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yep

amber jackal
# neon patio

Well, seems correct until 352/3, which isn't correct.

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Also, don't forget units.

neon patio
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wait is it 440/3

amber jackal
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Yeah, nice! And if you round it to an integer?

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Also, again, don't forget units.

neon patio
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147 seconds

amber jackal
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Great!

neon patio
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the mistake was 80 x 10 which I put 80 instead of 800 😅

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thank you

amber jackal
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Ah, I see.
You're welcome!

neon patio
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this would also work if I did it using the specific values from the start right?

amber jackal
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Yes. However, I advice against it.

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It's better to solve physics and chemistry problems generally, if possible.

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That is the usual approach, after all: you derive the formula, then substitute the values.

neon patio
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okay so steps are

  1. find the general equation for velocity in terms of v and t
  2. v=0 solve for t
  3. sub in the values to get t
amber jackal
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Yup.

neon patio
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okay thank you :)