#wtf is this
58 messages · Page 1 of 1 (latest)
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i neeed help with the whole question
i did it on my CAS calculator
i dont know what to do
Can you show how you did it?
i dont have my phone on me so i cant take picture rn
so i defined the function of c(x)
and then using the integral of -2,2 with c(x)
Alright. Whad did you get?
lieterally the same thing
What? Same as what?
its so dumb
like i solved it
and it gives me the same thing but this time the funtion is not defined and is still inside the integral formula and there is -4 at the end of it equaling zero
so integral-4=0
Sorry, I don't get what you mean.
The area of the cross-section would be the integral of (a(2 - b)^2 - C(x)) from -2 to 2. So, it should be a function of b.
The maximum value of C(x) is at x = ±2, which is a(2 - b)^2. So, the area of the cross-section is the area between y = C(x) and y = a(2 - b)^2.
hmmm im still so confused
Have you tried drawing the graph of C(x)?
yes its an open trapzeium
cross section of the barge
should i do this?
bro u there?
Yes, that would be the area.
Note that C(x) is even, so you can simplify the integral.
so i try the formula i showed u..?
bro how r u so smart
i got 4(a(2-b)^2- integral of c(x) of 2 ,-2
One sec, let me check.
No, I don't think it's quite correct. Can you show what you did?
alr give me 2 min
I don't quite understand how they got their answer, though.
As far as I understand, we need to find the volume of the whole barge, which will be the result of that integral multiplied by its length (10 m). So, it will depend on both a and b.
Don't use a calculator. Do it yourself.
i havent been taught on how to do this question by hand so my school has given us access to calculator as an aid
the whole paper is tech active
Oh...
Sorry, then I don't think I'll be able to help here. I'm not familiar with this approach of solving problems.
is there anyone who can help me
Maybe. If someone sees this post and they can help with this, they might.
why cant you do it?
I'm used to doing these kinds of problems by hand. Besides, I don't have a pocket calculator that can solve integrals. I don't think I've ever seen one.
dam alr thanks for your help
That doesn't make any sense. Calculators are for speeding up the grunt work of math, you still have to understand the process well enough to know what to input.
oh well then im not that smart