#continuity
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discontinuity of of different types
removable discontinuity is when there is a hole in graph
like for example (x+1)/(x+1)
its obviously 1 not at x=-1
yeah
at 0
yup but the catch is limit at that point exist
some cases limits dont exist
like in 1/x
we need to look for assymptotes
or maybe i am giving very simple examples
yeah what about cases with multiple points of discontinuity
some times discontinuity is like a jump in graph like in step x
if there is a problem i might explain better
in such questions i tend making graphs
(-1,1) is a small interval
and finding where 2x^2+1 is integers coz theres where discontinuity is
$f \circ g (x)= [2(2x-3)^2+1]$
for x <0
pratham
now this thing is discontinuous when the thing inside step is an integer ryt?
yeah
now i can see that at x=-1/2 its a integer
so its not continuous at that point
at '0' check left hand and right hand limit
if lhl and rhl are unequal its discontinuouus at that point
its equal
what's the answer then?
find out
is [t] like a stairs function ?
$f \circ g (x)= [2(2x+3)^2+1]$
for $x \geq 0$
pratham
floor function yes
no wait
well @violet adder this approach isnt efficient
there are so many points where the thing inside is integer
wow
yup thats a limit kinda thing ryt
say x=0
fog=19
so in (0,1) we might get discontinuity at
y=19,20,21,....,50 (coz 51 not incuded)
thats for x >= 0
i hope that makes sense
why?
so 32+31?
but f°g[-1/2]= f°g[1/2] right?
but 0 is only in one of the cases
oh