#Domain and Functions

34 messages · Page 1 of 1 (latest)

fallow prawnBOT
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languid kiln
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The range is the set of values of y.
So, for each value of y, solve y = 5x - 2 for x. That will give you the domain.

green pewter
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darpinger helping me altho its not my question

languid kiln
green pewter
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dude u alr helped me so i dont need to lol

ripe pivot
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how do I get 2 3 and 4

languid kiln
ripe pivot
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I'm so sorry, can you write out the steps I still don't follow.

languid kiln
ripe pivot
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Yes.

languid kiln
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Well, think of y = 5x - 2 as a linear equation, and solve for x.

ripe pivot
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I'm so sorry, can you write out the steps I still don't follow.

languid kiln
ripe pivot
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Using inverse operations correct?

languid kiln
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Well, yes.

ripe pivot
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I got 0.4

languid kiln
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Not sure what you did, but I meant an expression for x in terms of y.

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Well, let's look at our expression: y = 5x - 2. For convenience, let's switch sides:
5x - 2 = y
We want to express x. What should we do first?

ripe pivot
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add 2 to both sides

languid kiln
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Right. What do we get?

ripe pivot
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5x = 2y

languid kiln
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No. You multiplied the RHS by 2, while you should've added 2 instead.

ripe pivot
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5x = y + 2

languid kiln
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Yeah, nice! What next?

ripe pivot
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I'm not sure, normally it would stop here because you can't simplify further.

languid kiln
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Well, what should you do to 5x to make it x?

ripe pivot
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divide it by 5

languid kiln
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Yeah. So, we can divide both sides by 5.

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Which results in x = (y + 2)/5.

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So, we've expressed x. Now, for each value of y in the range of the function find the respective value of x. The set of those values would be the domain of the function.

ripe pivot
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Ok, I understand now! Thank you!

languid kiln
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Nice, you're welcome!