#Domain and Functions
34 messages · Page 1 of 1 (latest)
- Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close - Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
The range is the set of values of y.
So, for each value of y, solve y = 5x - 2 for x. That will give you the domain.
darpinger helping me altho its not my question
Please don't invade into other people's posts. Make your own.
dude u alr helped me so i dont need to lol
Yes, i get that but the answer for this is The domain is {2, 3, 4}
how do I get 2 3 and 4
As I said, express x from y = 5x - 2, then substitute the values of y from the domain.
I'm so sorry, can you write out the steps I still don't follow.
Do you know how to solve linear equations? Say, of the form ax + b = c.
Yes.
Well, think of y = 5x - 2 as a linear equation, and solve for x.
I'm so sorry, can you write out the steps I still don't follow.
You said that you know how to solve ax + b = c for x. What will the solution be?
Using inverse operations correct?
Well, yes.
I got 0.4
Not sure what you did, but I meant an expression for x in terms of y.
Well, let's look at our expression: y = 5x - 2. For convenience, let's switch sides:
5x - 2 = y
We want to express x. What should we do first?
add 2 to both sides
Right. What do we get?
5x = 2y
No. You multiplied the RHS by 2, while you should've added 2 instead.
5x = y + 2
Yeah, nice! What next?
I'm not sure, normally it would stop here because you can't simplify further.
Well, what should you do to 5x to make it x?
divide it by 5
Yeah. So, we can divide both sides by 5.
Which results in x = (y + 2)/5.
So, we've expressed x. Now, for each value of y in the range of the function find the respective value of x. The set of those values would be the domain of the function.
Ok, I understand now! Thank you!
Nice, you're welcome!