How do i turn sqrt(4+sqrt(8)) into a+b(sqrt of c) form
#algebra radicals
manic fractal
wet iceBOT
How do i turn sqrt(4+sqrt(8)) into a+b(sqrt of c) form
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spiral juniper
How do i turn sqrt(4+sqrt(8)) into a+b(sqrt of c) form
(a+b(rootc))^2 = 4 +2root2
I think
It might give an incorrect sol that way that you have to check though
manic fractal
(a+b(rootc))^2 = 4 +2root2
ye but its the sqrt version of it
like
sqrt(4+2root2)
thats not a+b(root c) form
cus theres a root infront of it
spiral juniper
sqrt(4+2root2)
Ye im squaring both sides
a^2 +2abrootc + cb^2 =4 +2root2
Yeah nah i think my way is cooked
manic fractal
i mean
its like this
root of (4 + 2 * root of (2 ) )
so like
2 times the square root of 2
add 4
and then square root the entire thing
and then turn that into a+b root c form
spiral juniper
But its a question you got right you didnt make up the numbers
manic fractal
yeah
spiral juniper
I think c is almost definitely 2
spiral juniper
nah I swear there is no way there is an answer to this
it makes sense if it was a 3 and not a 4
in the original q
inner path
How do i turn sqrt(4+sqrt(8)) into a+b(sqrt of c) form
oh my goodness i remember this form it’s so silly
forgot how to do it tho :(
however you can be lazy and let 4=sqrt16 and then factor
manic fractal
nah i figured it out