Help on vector problem

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[raw juniper]

a heading of 110 degrees is 340 degrees counterclockwise from the x axis, so the components for plane should be 300 cos 340degrees, 300sin 340 degrees?

a heading FROM 250 degrees should form a 20 degrees to the x axis

[raw juniper]

i dont rlly know if i should say it like this

since i originally calculated the resultant vector to be at (310.09, -92.34)

so maybe i should do tangent theta = -92.34/310.09 which will equate theta to negative 16.58 degrees

but then i dont know how to explain from there to get 106.58 degrees

[velvet bay]

this is the mistake
which quadrant would 250 degrees be in, and what would be the sign of the components?

[raw juniper]

250 degrees is in q3

but it comes from q3

its not the heading

this would be a rough sketch of the diagrams?

[velvet bay]

oh it does come from q3

mb

[velvet bay]

yea thats good

[velvet bay]

id just do this with quadrant analysis + reference angle

[raw juniper]

+close

[velvet bay]

+close