#integral

76 messages · Page 1 of 1 (latest)

gleaming vapor
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can i divide the integral by 2 like this

prime birchBOT
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delicate python
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What you can do is u substitution.

radiant portal
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No try to imagine it like a function , you have a function and have area between two limits diveded by 2 but you half both the limits . Will that be true ?

gleaming vapor
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yes right wouldn’t work thanks

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then how can i solve this

delicate python
gleaming vapor
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wait

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ok

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a is actually x

delicate python
delicate python
gleaming vapor
delicate python
gleaming vapor
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what part

delicate python
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The part I just explained.

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The part you just replied to.

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But didn't actually respond to.

gleaming vapor
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you mean like in the end you have a function like for example f (u) du and since everything is in u form you write it like f(x) dx?

delicate python
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...no.

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I mean.

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You have a function of x.

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You do a u substitution.

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You integrate.

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And then you reverse your substitution.

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Because your initial integrand was a function of x.

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Therefore your final answer must be a function of x.

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Do you know how to do u substitution at all?

gleaming vapor
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yes

delicate python
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Okay. Integrate (2x + 3)^2 using u substitution.

gleaming vapor
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sure

delicate python
# gleaming vapor

Why is your result a function of u? You integrated a function of x.

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A function of x.

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I mistyped.

gleaming vapor
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okay i can write it like 1/2.x3/3 +c

delicate python
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...okay, so differentiate that.

gleaming vapor
delicate python
gleaming vapor
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hmmm yes

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so i did it wrong?

delicate python
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Yes.

gleaming vapor
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where did i do it wrong

delicate python
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You can't just replace u with the letter x.

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You have to replace u with the equivalent value in terms of x.

gleaming vapor
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so 2x+3

delicate python
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Yes.

gleaming vapor
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yes yes i get it

delicate python
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So here's the thing.

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When you're doing a definite integral, you could do that.

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Or, equivalently, you could recalculate the bounds of integration to be in terms of u instead of x.

gleaming vapor
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yes i know that actually

delicate python
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...given that you didn't even know to plug back in the value of u after u substitution, I doubt it.

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But let's look at our first integral here. u = x + 1. So then our bounds of integration in terms of u are...?

gleaming vapor
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i actually knew it really… but used to always do it in definite integral and since there is only u , i converted it to x without thinking about it

delicate python
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...if you knew it, I don't know how you're having trouble on this problem, because it literally is just recalculating the bounds of integration in terms of u.

gleaming vapor
delicate python
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...so then you don't know how to recalculate the bounds of integration.

gleaming vapor
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ok i dont know z i actually know but i guess you wont tell me how to do it unless i say “i dont know”

delicate python
delicate python
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Look.

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We're integrating from x = a - 1 to x = a + 3. If u = x + 1, then when x = a - 1, u equals what?

gleaming vapor
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a

delicate python
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Right. And when x = a + 3, u equals what?

gleaming vapor
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a+4

delicate python
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Right.

gleaming vapor
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okay now i will try to solve it?

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can you wait

delicate python
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It's okay to not know things. We're here to teach you. You just need to admit to what you don't know so that we can teach you it.

gleaming vapor
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yes of course, but i just felt so humiliated because of the brain in your profile pic and the assertiveness in the way you write

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but its okay thanks

gleaming vapor