#Homothecies

12 messages · Page 1 of 1 (latest)

pine portal
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I'm in $\mathbb{A}^2$ and I have $O=(-1,0)$, $P=(2,3)$ and $P'=(0,1)$. I know that $f$ is an homothety, that $O$ is its centre and that $f(P)=P'$. I'm being asked for the matrix of $f$. I've found the matrix of $\vec{f}$ but I'm having trouble with the centre of it. How can I do it?

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true urchinBOT
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Miguel

pine portal
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I know the matrix has this form

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$\begin{pmatrix}
1 & 0 & 0 \
\alpha_1 & \frac{1}{3} & 0 \
\alpha_2 & 0 & \frac{1}{3}
\end{pmatrix}$

true urchinBOT
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Miguel

pine portal
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How do I find $\alpha_1$ and $\alpha_2$? I've tried $M(f)*0 = 0$ since it is the centre, but it is giving me the wrong answer, it just gives me $(-1,0)$

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Miguel

cinder rapids
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no

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obviously not

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we are strictly against it too