I need some hints on this one | Mathematics | Page 1

lofty cove May 29, 2024, 5:23 PM

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golden otterBOT May 29, 2024, 5:23 PM

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lofty cove

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ornate drum May 29, 2024, 5:25 PM

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Do you know your logarithm rules?

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What have you tried so far?

lofty cove May 29, 2024, 5:26 PM

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yes sir

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(2x+3)^(-1)

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2 can be log10(100)

ornate drum May 29, 2024, 5:27 PM

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lofty cove (2x+3)^(-1)

What did you do here exactly?

lofty cove May 29, 2024, 5:28 PM

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1/2 is in front of the logarithm so (2x+3) should have the power of -1

chilly cipher May 29, 2024, 5:28 PM

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power of 1/2

lofty cove May 29, 2024, 5:29 PM

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a

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i am so dumb

ornate drum May 29, 2024, 5:29 PM

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Don't call yourself dumb, it's ok

lofty cove May 29, 2024, 5:30 PM

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how do I continue with the power

ornate drum May 29, 2024, 5:31 PM

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So $\frac12\log_{10}{(2x+3)}=\log_{10}{(2x+3)^{\frac12}}$

glass oreBOT May 29, 2024, 5:31 PM

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Lumberdude #MakeWolfOwner

ornate drum May 29, 2024, 5:32 PM

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That means that with all you have done we now have

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$\log_{10}(x+9)+\log_{10}(100)=\log_{10}{(2x+3)^{\frac12}}-\log_{10}(25)$

glass oreBOT May 29, 2024, 5:33 PM

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Lumberdude #MakeWolfOwner

ornate drum May 29, 2024, 5:34 PM

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Any way to simplify it, by combining terms?

lofty cove May 29, 2024, 5:34 PM

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log10(x+9/100)=log10((2x+3)^1/2)/25

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I think I got it now

ornate drum May 29, 2024, 5:35 PM

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Are you sure about this?

lofty cove May 29, 2024, 5:35 PM

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wait a sec

ornate drum May 29, 2024, 5:35 PM

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Wait, I will show what you typed out

lofty cove May 29, 2024, 5:36 PM

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isn't it log10(x+9) - log10(100) ?

ornate drum May 29, 2024, 5:36 PM

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$\frac{\log_{10}(x+9)}{100}=\frac{\log_{10}{(2x+3)^{\frac12}}}{25}$

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Is this what you meant?

glass oreBOT May 29, 2024, 5:36 PM

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Lumberdude #MakeWolfOwner

lofty cove May 29, 2024, 5:37 PM

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lofty cove

^

lofty cove May 29, 2024, 5:37 PM

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glass ore **Lumberdude \#MakeWolfOwner**

yes

ornate drum May 29, 2024, 5:37 PM

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lofty cove ^

Oh yeah you're right, it should be minus

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Wait

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$\log_ab+\log_ac=\log_ab\cdot c$

glass oreBOT May 29, 2024, 5:39 PM

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Lumberdude #MakeWolfOwner

ornate drum May 29, 2024, 5:40 PM

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And:
$\log_ab-\log_ac=\log_a\left(\frac{b}{c}\right)$

glass oreBOT May 29, 2024, 5:40 PM

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Lumberdude #MakeWolfOwner

lofty cove May 29, 2024, 5:40 PM

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yes

ornate drum May 29, 2024, 5:40 PM

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glass ore **Lumberdude \#MakeWolfOwner**

Then this is not correct right?

lofty cove May 29, 2024, 5:41 PM

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Yes it is because it was - from the begining

ornate drum May 29, 2024, 5:41 PM

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But should the numbers not be inside of the logarithm?

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loga(x/y)=/=log(x)/y

lofty cove May 29, 2024, 5:43 PM

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just a sec

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Thanks for the help though!

ornate drum May 29, 2024, 5:45 PM

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No problem

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You got the rest from here right?

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Do tell when you're stuck tho

worn field May 29, 2024, 5:45 PM

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Don't forget your domain is what I'd like to add

lofty cove May 29, 2024, 5:45 PM

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ornate drum Do tell when you're stuck tho

ok

ornate drum May 29, 2024, 5:49 PM

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worn field Don't forget your domain is what I'd like to add

Great point!

lofty cove May 29, 2024, 5:54 PM

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Made it.

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Thanks for the help

ornate drum May 29, 2024, 5:55 PM

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lofty cove Made it.

Nice! Well done man!

lofty cove May 29, 2024, 5:59 PM

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+close

#I need some hints on this one