#calculus
21 messages · Page 1 of 1 (latest)
roi
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Set ln(x)=u and think of the identity $sin^2(x)=\frac{1-cos(2x)}{2}$
Rotor
but how do i integrate the cos function after that?
The integrand is not defined everywhere. Does your integral come from an exercise and if yes are there limits of integration?
They probably just have to find the antiderivative but you are right, better be sure
With the change of variables you get $\int sin^{2}(u)e^{u}du$
Rotor
why e^u?
With the change of variables
You have $ln(x)=u$ so $x=e^{u} $ thus $dx=e^{u}du$
Rotor
Now use the identity here
The biggest difficulty here is calculating $\int \frac{cos(2u)e^{u}}{2} du$
Rotor
Which you can do via double integration by parts or you can use complex analysis and the linearity of Re:z—>Re(z) by setting cos(2x)=Re(e^{2ix})
If you don’t know the latter the former is good as well
+close