#Inverse trigo

63 messages · Page 1 of 1 (latest)

fading shard
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I made cases but couldnt really match my answer

pliant brookBOT
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sturdy solar
fading shard
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its from -3 to 3

sturdy solar
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...no.

fading shard
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how

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like not included

sturdy solar
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Because "from -3 to 3" isn't the expression inside of arctan.

fading shard
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wdym by arc tan

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inverse?

sturdy solar
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Inverse tangent, also known as arctangent.

fading shard
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oh

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bro its given in the end

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0<|y|<3

sturdy solar
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That is not the expression inside of arctan.

fading shard
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im talkkin about y

sturdy solar
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I know you are. I don't know why, because I'm not.

fading shard
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😭

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bruh

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the input right

sturdy solar
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Of arctan.

fading shard
sturdy solar
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Right.

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And what's the input of arccot?

fading shard
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reciprocal of that

sturdy solar
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Right. So what does that mean?

fading shard
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need to make cases...

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They both belonga to different range so i guess we need to make cases

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before converting cot to tan

sturdy solar
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Okay. So make the cases.

fading shard
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I did

sturdy solar
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And what are they? In terms of 6y/(9 - y^2)?

fading shard
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like

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when

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y is +ve

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we can reci[rpcal that

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but if -ve

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oh wait im confused over -ve

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its gonna pie + ?

sturdy solar
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Look. Let x = 6y/(9 - y^2). Then what we have is arctan(x) + arccot(1/x).

fading shard
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right

sturdy solar
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So you're correct that we split it into cases x > 0 and x < 0.

fading shard
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yeah

sturdy solar
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Let's consider - wait, have you studied calculus at all?

fading shard
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yes

sturdy solar
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Okay, so I can talk about limits.

fading shard
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yeah

sturdy solar
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What's the limit as x approaches 0 from below of arccot(1/x)?

fading shard
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idk havent dont limits on inverse yet

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ig 0 tho

sturdy solar
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No.

fading shard
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okay

sturdy solar
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The limit as x approaches 0 from below of 1/x is negative infinity, right?

fading shard
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wait

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you sure

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wont it depend

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ig thats infinity

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like shouldnt that be 0-

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I have to go rn gonna come tomorrow again thanks for the help tho

sturdy solar
fading shard
sturdy solar
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Right. So it's the limit as u goes to minus infinity of arccot(u).