#i need help Asap
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huh?
how do i solve part be
that doesnt matter
i cant help you i am sorry
ohh okay
What does it mean for an equation to have a tangent? What are the requirements for the tangent line?
like the line on a curve
like the red line
Yes, but what conditions does this impose on the tangent line?
I don't know tbh
hi taffy
Hi
What does it mean for something to be tangent to something else?
Bro the answer of b is?
First you need a
Why are you throwing around answers man
Don't be like that. The person asking is learning
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For a) part id say differentiate the equation by which you will get the dy/dx and put x = 1 which will get you the slope of the tangent
then using y =mx +c you can find the equation putting the values
NOW FOR PART B
THIS IS WHAT I DID I AM NOT SURE OF HOW CORRECT IT IS
Keep the dy/dx = slope which coming out to be 4
then you will get two values of x
solving the quadratic
one will be 1
and then take the other value and put that in y = 4x + 1
youll get the y coordinate with respect to the second value
(NVM ITS WRONG JUST REALISED)
I have one more solution
equal the tangent to the curve
and then
Take the roots as A,B,C
then A+B+C = -(coeff of x^2)/coeff of x^3
take any one root to be 1
like this youll get the equations
and fine the roots and put its value in the curve to get y
the answer is coming -1.5,-5
What does it mean for two equations to be equal to each other? Hint: what sort of root are you taking
And what does a root of a polynomial mean wrt factoring it?
could you write down the full equation. I'm struggling to visualise
@karmic saddle I will help explain why this is true
As CosmicMan said, we equate the formulae of the y-coordinates of the curve and the tangent line to find their intersections
2x^3 - x^2 + 4 = 4x + 1
2x^3 - x^2 - 4x + 3 = 0
The sum of the coefficients of 2x^3 - x^2 - 4x + 3 is 0, which means 2x^3 - x^2 - 4x + 3 evaluated at 1 has value 0.
This implies that x - 1 is a factor of 2x^3 - x^2 - 4x + 3, by factor theorem.
Then you may feel free to continue on CosmicMan's steps, or even take long division between 2x^3 - x^2 - 4x + 3 and x - 1 and proceed to factorize the quotient, which is quadratic
No reason to do this work though, as the question a) already told us that x=1 was a root of their difference.
But it is a useful thing to check when going over roots of polynomials
Ah, very true
@frozen tiger I understand what youre saying right but how to i factorise without using long division
As CosmicMan suggested, you can solve for the roots using Vieta's formulae:
https://en.wikipedia.org/wiki/Vieta's_formulas
How did you get the factors x + 1 and 2x + 3?
One of those factors is incorrect the others are correct
nope except 1 both are incorrect
2x + 3 and substituting -2/3 lolz
ooh lol.. how the hell i got these factors 🫢
EDITT:
Sorry the last step of factorisation is incorrect.
The correct factors are (x-1)(x-1)(2x+3)
find the derivative and value of $2x^3 - x^2 + 4$ at $x = 1$ and check if they agree with $y = 4x + 1$
赤色のシャナ
that's basically it
the explanation is that tangent lines have a specific condition that they need to satisfy that forces them to have the same slope as is the derivative of the curve at the point it is tanget to.
in other words, it's basically how the derivative works. think about it
Why x = 5, and why does the derivative need to agree with that of the straight line? The question seems to only require the curve and the straight line meet elsewhere