#someone pls explain what R-> R is to me in 'f:R -> R, f(x) = x^2'
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You can think of the domain as the set of valid inputs
for the function
Well, exactly that
is it different to 'domain of f(x)'?
f(x) is not a function
it is the output value of the function, when you give x as an input
A function is like a microwave
x is the food
from where ive been learning ive had questions like 'find the domain or range of f(x)'
f(x) is the warm food
Well, formally it should be the domain or range of f
But at this point most people don't bother to make the distinction
For no valid reason.
hm aight thats pretty interesting
ill keep that in mind
so what would the colon inbetween f: R - > R mean then
It's just an indicator
I guess similarly to the "notice" of a microwave
don't put aluminium inside

ahhh
and the arrow?
thats the same as (R, R) right
even though that wouldnt make sense
f : D -> R, is a function that takes inputs in D and provides outputs in R
the arrow here is also standard notation
for that "notice"
so if i did f : 3 -> A, then everything following from 3 comes out as A
3 is not a set
You can think of this example, f : R -> {-1, 0, 1}
R is the set of real numbers
and {-1, 0, 1} is a set that contains the three elements -1, 0 and 1
so R -> {-1, 0, 1} from my own understanding, is trying to say there can be any real numbers inbetween the set of {-1, 0, 1}
no
f : R -> {-1, 0, 1}
it means that you have a function f
that takes input values x in R
and you know for sure
that f(x) is either -1, 0 or 1
according to this notice, it cannot be anything else
👍
so here's another example
f : {3} -> R
is a function that can take nothing but 3 as an input
R -> {-1, 0, 1} means it takes nothing but {-1, 0, 1} as the input
no, it returns -1, 0, or 1 as the OUTPUT
the input can be any real number in R
the source of the arrow indicates the input set
and the end of the arrow indicates the output set
okay
okay
okay
my eyes are being opened
so if in the set or R,
we input for say 2
nothing will happen
because the outputs are limited to -1, 0 and 1
if what i said is right then i completely get it
Well, yes indeed
f(2) will be either -1, 0 or 1
if f : R -> {-1, 0, 1}
on the other hand, for g : {3} -> R
you CANNOT feed 2 to g
it's like putting a banana in a microwave, when they explicitly tell you that you can only put cooked dishes
how so?
for instance, let $f : \mathbb{R} \rightarrow \mathbb{R}$ defined by the relation: for any $x \in \mathbb{R}$, $$f(x) = x^2$$
Rion
Here, it is clear that for any $x \in \mathbb{R}, f(x) \geq 0$
Rion
However, for a subset $A$ of $\mathbb{R}$, we define:
$$f[A] = { f(x) | x \in A}$$
Rion
In particular, $f[\mathbb{R}]$ does not contain negative numbers
Rion
im sorry thats a bit too advanced for what im up to currently
so i dont really get that
but i understand the two notations are separate
and i think thats all ill need to know for now mostly