Green Theorem's

[short thorn]

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[tall cobalt]

well.. just determine the equivalent double integral given by Green's, then compute said double integral

[oak fog]

i don't quite know the range for the variable to integrate

[tall cobalt]

the region has circular symmtery since it's a sector of a circle

so switch to polar and determine the angle and radii bounds

[oak fog]

so the line segement has nothing to do for the integration? I found out that the r is from 0 to 2 and angle of 45degree but the answer is negative

[tall cobalt]

the line segments tell you what the region of integration is

so yeah, you have $\iint_D(-2x-2xy)\dd{A}=-2\int_0^2\int_0^{\pi/4}[r\cos(t)+r^2\cos(t)\sin(t)]r\dd{t}\dd{r}$

[civic folio]

Omegabet_

[oak fog]

okay thank you so much

[oak fog]

sorry but i just saw that isnt greens theorem integrating from the Q part then the P part and the answer i get is negative i think is incorrect?

I got this

[tall cobalt]

check with a calculator