i always fail to solve these typa questions

[dawn thistle]

someone help me, i always can't solve this problem at all

[tranquil inlet]

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[tiny ridge]

Well 8=2^3

[long wind]

Use log to find x

By applying log both sides

[dawn thistle]

hmm

[dawn thistle]

how?

teacher never told me how to do that

[tiny ridge]

No need here I think

[tiny ridge]

also 8^-x=1/8^x

[dawn thistle]

correct

nice

[tiny ridge]

So express 8^x in terms of 2^x

Using the fact that 8=2^3

[dawn thistle]

so 8= 2³

[tiny ridge]

Yep

[dawn thistle]

how do i get the answer then

[tiny ridge]

Well 8^x=(2^3)^x

Do you agree ?

Now use the properties of powers

[dawn thistle]

aaa

im having a stroke

[tiny ridge]

do you know the properties of powers ?

[dawn thistle]

idk whats properties

[tiny ridge]

well like (a^b)^c=a^bc

[dawn thistle]

uujhhuhhuhhuhhhhhhhhhh

can u just give me straight answer

[tiny ridge]

nah you have to understand, the answer is almost here you just need to apply the property

Lemme explain

you know that 2^x=3

And like I said before 8^-x= 1/8^x

Do you understand thus far ?

@dawn thistle

[dawn thistle]

yes

(1/8)^x?

[tiny ridge]

Yes if you want it’s the same

[long wind]

Hey rotor

Actually i m studying definition of limits but

[tiny ridge]

Yes?

[long wind]

I can't understand not a bit

I know how to solve limits btw

[tiny ridge]

If you need help open your own channel

[long wind]

Can i text you?

[tiny ridge]

sure i don’t mind

Now @dawn thistle , like I said 8=2^3

[dawn thistle]

alr

[tiny ridge]

So (1/8)^x=(1/2^3)^x

=1/(2^3)^x

Tell me if you don’t understand

[dawn thistle]

that's not how teacher told me how to solve it

someone showed me how to Log it

[tiny ridge]

I mean sure you can apply the logarithm but I think it’s unnecessary here

but if your teacher said to solve it that way then do it

[dawn thistle]

why is it unnecessary

[dawn thistle]

idk how to

[tiny ridge]

You don t need to find x here

Just 8^-x which doesn’t require x just 2^x

But we can do it with log if your teacher wants you to do it that way

[dawn thistle]

i got X then i put the result in calc like this
8^-result

[tiny ridge]

If 2^x=3 how do you find x?

[tiny ridge]

Good

[dawn thistle]

aaaaaaaaaaaaaa wait

[dawn thistle]

log2(3)

[tiny ridge]

Yes !

Now you can find 8^-x

[dawn thistle]

this is much more simpler than doing it manually frfr

[long ginkgo]

Matter of experience

[tiny ridge]

I think it’s simpler the way I said it but oh well

[long ginkgo]

Hard agree, rotor

[dawn thistle]

@long ginkgo @tiny ridge

isnt that just simple

[long ginkgo]

Having to fill it in alone takes twice the time to just do it in your head from the fact that you know 2^x

But if you're not comfortable with exponent rules yet then you're entirely correct

[dawn thistle]

how to do it in my head

[long ginkgo]

8^-x=(2^3)^-x=(2^x)^-3=3^-3=1/27

[dawn thistle]

wtf

i think ima js stick with calculator method

+close