Q eqs and Trig

[normal orchid]

Can someone give me an explanation for 25th question? dont hit and try, anyone can do that.

[junior cape]

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[warped river]

For what value of p will this have no real roots in x?

[normal orchid]

yeah, it's something related with the discriminant

so I tried simplifying by using b^2 - 4ac but i didnt get a clear answer

[warped river]

What did you get for the discriminant?

[normal orchid]

(cosp - 2sinp)^2 + 4(1- sinp) (sinp)

[warped river]

Are you sure that the first term there is correct?

[normal orchid]

100%

tried this 4 times, got the same result

[warped river]

b ≠ cosp - 2sinp, tho

It is just cos(p)

Doesn't make it easier tho

[normal orchid]

cos^2p - 4(cosp-1)(sinp) yeah?

[warped river]

Yeah

[normal orchid]

simplify it, you'll get this

[warped river]

Check your coefficients too for the bounds

[normal orchid]

wait

[normal orchid]

Actually, the question in itself isn't that hard

it's just phrased awfully bad

[warped river]

You can honestly also just plug in and check lmao

[normal orchid]

☠️ nahh dawg I aint satisfied with that

[warped river]

Same

I would be severely disappointed in you

[normal orchid]

So it might as well be D >/= 0

[warped river]

But I think the p-values for which the discriminant is 0 are non-trivial

[normal orchid]

Should I try expanding the binomial?

(cosp - 2sinp)^2 this

[modest depot]

Don't you have the normal
cos²p - 4(cosp - 1)(sinp) > 0?

[normal orchid]

so that would just be Sinp >/= 0 ?

[warped river]

≥

[normal orchid]

OHHH

MAKES SENSE

The answer should be P belongs to (0, pi) if im not wrong

[modest depot]

Yeah

[normal orchid]

Nicee

Thanks man

Its phrased badly

[modest depot]

👍

[normal orchid]

how do u close

[untold pond]

hi

can i ask my question here

[normal orchid]

ok sure

i was boutta close

[modest depot]

Lol

[untold pond]

how to solve this

[normal orchid]

apply Log 27 base 3 both side

[warped river]

I don't think that's the answer tbh

[untold pond]

WHAT

[normal orchid]

youll get value of X

[warped river]

Fill in the right bound

[untold pond]

I CAN DO IT ON CALC?

[normal orchid]

? you haven't studied Logarithms?

[normal orchid]

Yeah

[untold pond]

i dont use log on calculator

how do i do it

[normal orchid]

well do it on paper, it's quite easy

[untold pond]

how

[warped river]

Rewrite 8^{-x}

[untold pond]

i would prefer calc

[normal orchid]

3 can be simplified into Log 27 base 3

[warped river]

To the answer you know 2^(something times x)

[untold pond]

btw 27 is one of the answers in the multiple choices

[normal orchid]

we aren't allowed to use Calculators here 😔

[modest depot]

Where you from

[untold pond]

egypt

[untold pond]

how

[modest depot]

Oh👍

8^(-x) = 1/8^x

[untold pond]

not in the answers

[warped river]

Not that weird, considering x hasn't been put in

What is 8 expressed in 2^a?

[normal orchid]

well see here

2^x = 3 can be expressed as Log3 base 2

[untold pond]

2³

[normal orchid]

plug that in a calculator, you'll get the value of x

[untold pond]

ok wait

[normal orchid]

fair enoughs gg

[warped river]

Exactly!

Now remember $a^{b*x}=(a^x)^b$

[untold pond]

doesnt give me x

[zinc ruin]

Lumberdude #LeaveWolfAsHeIs

[normal orchid]

oh?

it's roughly

1.5

[normal orchid]

I believe the answer is C

well, there is a better way to solve this, but i cant rlly remember the logarithmic properties ☠️

[untold pond]

wait

[warped river]

Bruh I was helping them, why tell them the answer instead of giving them the joy of solving

[normal orchid]

Well, they use a calculator generally either way.

[untold pond]

this gives me 1.584962501

right?

[normal orchid]

I'm pretty sure people dodge the values of Logarithm

[normal orchid]

yup

[untold pond]

calling it joy is wild

@normal orchid thanks for giving me the calc method 💯

[normal orchid]

Now, apply the first three decimal values on 8^-x on your calculator

[humble nest]

@untold pond has given 1 rep to @normal orchid

[normal orchid]

So now

Plug in

[warped river]

Don't use a calculator, just rewrite the 8^-x to (2^x)^-3, where 2^x=3, 3^-3=?

[normal orchid]

8^ (-1.585)

[untold pond]

i did 8^-Ans

[normal orchid]

You'll get 27.00.. sm

Decimal points can be neglected if you use calc, so the answer will be C

[untold pond]

that's COMPLICATED 😭

[normal orchid]

well, in my opinion it's a more natural way of approaching the question

you connect with the question and it is insanely gratifying when you do it and get the end result.

[warped river]

It is at first, better to struggle now than not knowing at all what to do during the exam

[normal orchid]

Anyway, I wouldn't want to hinder with any of your opinions, as long as you're satisfied with the result, that's all we all want isn't it (:. Cheers

[untold pond]

the more sane way of approaching a mathematical question is by using a calculator

[untold pond]

in exam i use calc lol

[warped river]

Plus you're not reliant on errors from the calculator

NVM then

[untold pond]

calc ain't pulling no errors

[normal orchid]

for a second I thought you were referring to caculus when u said Calc 😭

[untold pond]

on that question

[normal orchid]

I was like why this person asking Calculus method to solve a Logarithm

[warped river]

It so does tho

Numerical errors

[untold pond]

im in grade 9 bruh 😭

[normal orchid]

ye its all good

ill close this now

[warped river]

You'll learn your exponent rules later anyway

[normal orchid]

yup

[median garden]

The tickets system is disabled for this server. Enable it at: https://yagpdb.xyz/manage/624314920158232616/tickets/settings.

[untold pond]

i have been facing this question since grade 5

[warped river]

+close does the trick

[normal orchid]

+close