#Taylor remainder
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It depends on the function doesn't it
What is the expression of the remainder?
i used this formula
the taylor poly is centered around 0
I would have thought the remainder is a series
Well never mind that
Do you have an upper bound for the third derivative?
yeah
this
No I mean how did you derive an upper bound of the third derivative
ohh
yes
Since c is somewhere in between
i got the fourth derivative so i can get the critical points for the third
i set the function to 0 and then applied the quadratic formula
and found two zeros
one of the points was outside [0,1], so i didn't use it
Out of curiosity
yes
Did you make sure that it was not a local min?
The critical point I mean
Because it might be that the max is at a bound
Ok, sure
Otherwise just compute the second derivative of f³
At your critical point
It's not too much of a tedious check I think
Other than that I have nothing to complain about regarding the method itself
It is logically sound
okay
thank you so much
So good job on that
@soft wasp has given 1 rep to @chrome apex