#Finding limit and convergence of integral
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Is it the integral of x^2n/(x^2+x+3 + cos(x)^2024) ?
If so then the the integral definitely converges because the function is continuous on [0;1]
Oh you need to calculate the limit for n approaching infinity ?
Here, if x is on the interval [0,1[ what’s the limit of x^2n as n approaches infinity ?
It’s fine dw
Yes but when you integrate on [0;1[ or [0,1] it’s the same because continuous by parts function when integrated on an interval are equal by finite parts differences so if you integrate on [0,1] or on [0,1[ it’s the same
Yes
But you need to justify interverting the limit and integral
ie use the dominated convergence theorem, have you heard of it ?
Well here if you want to find the limit you need to consider the limit inside the integral
The problem is you aren’t guaranteed to be allowed to switch limit and integral here it works but still
Haven’t heard of it what’s the claw criterion?
Oh it’s fine if you haven’t heard of it it’s my bad you must use another method then
Oh okay I see
Well here you can see that the integral is always positive
And consider that 1/(x^2+x+cos(x)^2024 +3) <=1
For any x on that interval
Yes
You get 1/(2n+1)
@copper phoenix has given 1 rep to @river raft
Np I’m sorry I should have thinked simpler lol idk why I used complicated theorems