#help with this simple probability problem
58 messages · Page 1 of 1 (latest)
- Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close - Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
You can use hypergeometric distribution here.
Use permutations and combinations and solve it
Holdon I don't know that yet, I'm on the very basic level of probability
28/48×27/47×26/46
tf
Here you multiply the variables like I did
Cause probably is multiplied when you are taking 2 or more cases
This this case you multiply the probability thrice
Do you mean independent events
Yep
My answer is way off I used combination
Ah, no problem.
Suppose you have N objects, D of which are marked.
You take a sample of n objects. Then the number X of marked objects in the sample follows a hypergeometric distribution: X ~ HG(N, D, n).
Its PMF is:
P(X = k) = C(D, k) C(N - D, n - k)/C(N, n)
Here C(n, k) = n!/(k! (n - k)!) is the binomial coefficient.
And probability formula is p(x)=no of favorable outcomes /total number of outcomes
Yessir that's how u solve it
what is the answer anyways
The probability of picking a boy in the class will be 5/12 and for girls it'll be 7/12
Favorable outcomes start with 28 and total outcomes start with 48
Lmfao my stupid ass got 3276/17296 simplified to 819/4324
Howd you even get that 😭
I dont know what I'm doing 😭😭
Did you simplify the permutation
C(28,3)/C(48,3)
Is this for (a)?
Yes
Alright, nice!
Am I hopeless
And for (b)?
Probability of all 3 community members being girls is given by 28C3/48C3
Uhhm let me check
2 boys one girl would be
Let Scepter try first.
20C3 x 28C3/ 48C3
yeah my bad
Well, that's incorrect, anyway.
I'm getting 0.189407955596669 for a
Use ordinary fractions.
Damn
I used a calculator
Well, then don't.
It's C(20, 2) × C(28, 1) / C(48, 3)
Nice!
Ye
Now, just simplify both answers a bit. The numbers aren't too big, so you can do it by hand.
plugs it in on a fraction calculator
No, don't use a calculator.
+close