#Probability
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What have you tried?
My initial idea was to find the probability of winning in each of the situations. In situation A, it's easier, since theoretically it's 1 in 10 (assuming each person buys 1 ticket). But for situation B, I got a little confused. I thought maybe I could do a combination of 344 choose 9 to find the total number of possibilities (allowing all names to repeat) or maybe a permutation of 344 choose 9. Idk.
Okay, so you know $P(A) + P(\bar A) = 1$, right?
Techie Literate
I didn't know. Is it a formula? If so, I don't think I've ever seen it. I might also just be having trouble interpreting it due to the language, I'm a native of Brazil so naturally I speak Portuguese and here the symbols for some quantities are different depending on the textbook used for study.
Does it have anything to do with this formula? I saw it on a website.