#differential
32 messages · Page 1 of 1 (latest)
- Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close - Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
I disagree with the given answer.
No need.
First of all, note that this function is differentiable everywhere it's continuous. So, check for continuity first.
Yeah, at x = 0 it isn't continuous, so it isn't differentiable there, either.
As for x = 1, try just substituting it. Do you get an expression you can evaluate without using limits?
Well, in any case, that is undefined by itself. So, doesn't exist.
Is this correct sir?
Thus, f(x) is undefined for x = 1. So, also not differentiable there.
X=1 should be defined first
However, what I think happened here is that these are supposed to be 1, not 0.
If we change those to 1, then the given answer would be correct.
Well, the function will become continuous at x = 1. However, it still won't be differentiable there.
Try proving that.
Well, rather, the limit doesn't exist. But yeah, in any case, the derivative doesn't exist at x = 1.
No worries, you'll get better with practice.
You're welcome!