#help grade 8 desperately

589 messages Ā· Page 1 of 1 (latest)

compact rampartBOT
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    +close
    
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  5. Do not ping the mods, unless someone is breaking the rules.
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mortal mango
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i've done this so far but am 99% sure it is wrong:

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also am currently last minute studying and am about to go to bed soon so may not reply if u reply after like an hour

mortal mango
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help grade 8 desperately

bright junco
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hi have an idea of the answer

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am not sure if its right tho

mortal mango
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yoo

bright junco
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yello

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so, if the area of EFGH is 25 m^2, then each side= 5 m

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EF=EH=HG=GF=5m

mortal mango
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or does that still work even tho it rectangle

bright junco
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it says ABCD is a rectangle

mortal mango
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if they're expanded by the same ratio wouldn't that also make EFGH a rectangle?

bright junco
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even so, try substituting lxb=area of rectangle

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so that means l x b=25m^2

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there are no other combinations

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factors of 25 are 1,5 and 25. So hence EFGH has to be a square.

mortal mango
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ooohhh

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i see i see

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yeah that makes alot more sense now

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hold on

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so would r just be 5?

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if sides of abcd are 1m

bright junco
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i suppose so.

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wait

mortal mango
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could there be decimals or smth?

bright junco
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let's try substituting that into the pythagoreas thereom

mortal mango
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oh

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ye

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true true

bright junco
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so hypotenuse= 5m

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so if r=5 then AE=5m

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that doesnt sound right.

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instead, we can use the method of trial and error

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take AE as x, and AF as y.

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EF^2 = AE^2 + AF^2

mortal mango
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hold on would r be 4 instead?

bright junco
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25= AE^2 +AF^2

mortal mango
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wait

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nvm

bright junco
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yes, and AF = 3

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but we can take AE as 3, and AF as 4

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since AE is shorter than AF on the diagram

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So answer could be r=3

mortal mango
bright junco
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pythagoreas theorem

mortal mango
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the a^2 + b^2 = c^2 thingo

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hol on

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brain not braining

bright junco
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yup

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no, youre on the right track

mortal mango
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wait

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ooh

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AE^2 is a^2 in the theorem and AF^2 is b^2 in the theorem which is 25 or 5^2 (c^2 in the theorem)

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is that it?

bright junco
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nonononoo

mortal mango
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oh crap

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oh wiat

bright junco
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so a^2 is the hypotenuse of the triangle, so a^2 = EF

bright junco
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hypotenuse is the longest side on the traingle

mortal mango
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i

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i'll just let u explain first and thern ask questions after

bright junco
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that's alright, feel free to ask me anything. It's best to clear ur doubts on the go. If not the whole thing will collapse

mortal mango
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ooh ok

mortal mango
bright junco
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alright, would ya like me to start from the start?

mortal mango
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yeah just go from start

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and i will see where i stop understanding

bright junco
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okay, so let's get things straight

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so area of EFGH is 25m^2. To find the sides we can substitute the values onto the area of a square formula. Area = Side x side.

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so, 25m^2= 5m x 5m

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hence, EF is 5m.

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Ef = FG = HG = HE = 5m

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so now, to find out the value of AE and AF we needa use the pythagoreas theorem

bright junco
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right?

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because using pythagoreas theorem:

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wait

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sorry

mortal mango
bright junco
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EF^2 = AF^2 + AE^2

mortal mango
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ye

bright junco
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5^2 = 3^2 + 4^2

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right?

mortal mango
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yeah

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but i dont understand the trial and error part

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what did we assume AF and AE were before?

bright junco
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we assumed it as 3 and 4

mortal mango
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wait why tho

bright junco
mortal mango
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wait

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oooh

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ooooohohhhhhh

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ok yeah contine

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my brain died there

mortal mango
bright junco
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wanna dm me?

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we can voice call ad it'll make it easier for u to understand

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only if ya wanna?

mortal mango
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i dont think i can talk rn

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cuz no mic

bright junco
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that's aight,

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i'll just type

mortal mango
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ye

bright junco
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so given in the question AE = r multiplied by AD, right?

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and AE = 3m

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so, 3m = r x AD

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AD is most probably 1. and hence r = 3

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i think. I hope it's right

mortal mango
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ooh

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wait i think i see now

bright junco
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yea, try 3

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when will ya get the results back?

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is it like homework or?

mortal mango
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nah it's prac test question

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but there are no answers :/

bright junco
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who will check it then?

mortal mango
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idk lmao

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it's some math comp thing

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and past paper

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let me see if i can find answers to these papers

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yea there's no solutions for it

bright junco
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darn

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maybe u can ask ur friends what they got, and cross check

mortal mango
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ye i'll ask this one smart guy tmrw

bright junco
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wait, is this grade 8>

mortal mango
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and then update u on what he got

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yeah grade 8

bright junco
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i dont remember grade 8 having questions like this..

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darn i have bad memory

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how old are u?

mortal mango
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13

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well it's grade 7 and 8

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some problem solving math comp

bright junco
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turning 13 this yr?

mortal mango
bright junco
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no way, me too

mortal mango
#

yoo

bright junco
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but am not in grade 8 tho

mortal mango
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wat

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grade 9?

bright junco
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yea, i might skip to grade 10 tho

mortal mango
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tf

bright junco
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fingers crossed

mortal mango
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so u are rlly smart

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basically

bright junco
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i wouldnt say am rlly smart

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im okay level

mortal mango
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lmao u are gonna skip two grades

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but alr

bright junco
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are ya from the US?

mortal mango
mortal mango
mortal mango
bright junco
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ohh, am in the UK

mortal mango
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ooh

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are you born early 2010?

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wait

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yeah

mortal mango
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there are some 2011s in my class

bright junco
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no, late december

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like a week before new years

mortal mango
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wait wat

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so did u skip a grade?

bright junco
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im born on december 24

mortal mango
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or uk school just better

bright junco
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if i was born on 2010 early before July. then i would be in yr 10

mortal mango
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huuhhhh

bright junco
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but since am late december am in yr 9

mortal mango
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uk school one year ahead of australia

bright junco
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bc we gotta study till yr 13

mortal mango
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oh

bright junco
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which year do u gotta study till?

mortal mango
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12

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whaat

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year 13

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i've never heard of that wtf

bright junco
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yea, things are different

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🤣

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frfr

mortal mango
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i thought uk education was similar to australia education

bright junco
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it's called the sixth form. yr12-13

mortal mango
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sixth form?

bright junco
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yea lol

mortal mango
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hold on so your education is a full year ahead of ours

bright junco
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Wales, Ireland and the whole of Uk follow em

bright junco
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when does ur school yr start? mine starts on september and ill be in yr 9 then

mortal mango
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february

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i think

bright junco
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you think? 🤣

mortal mango
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uh

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well tbh idek

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early next year

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is all ik

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which makes sense cuz new year so u go up a grade

bright junco
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yea, so you'll be in yr 9 on a february 2025. whereas ill be in yr 9 on a september 2024

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practically just 4 months apart.

mortal mango
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wait i thought u in grade 9 rn

bright junco
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wait that's where things get complicated

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so, am not in England rn. am at mah gma's at another school

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in which am in grade 9

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it's complicated

mortal mango
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so u grade 9 at one school and grade 8 at another

bright junco
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which is why i wanna be in grade 10 tis september

bright junco
mortal mango
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i thought u were grade 11 or smth because what is this stuff:

bright junco
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oh that's stuff that i know

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i dont learn it in school. but i study outside of school

mortal mango
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oooh

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so yeah u are smart basically

bright junco
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no

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am dumb

mortal mango
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lol ok

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oh ye the question i showed u was 1 out of 5 on a past paper that u have 2 hours to complete

bright junco
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how much time u have left? or did u complete the test?

mortal mango
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oh no i'm taking it tmrw

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was just doing last minute study

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practise questions

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cuz idk how ur meant to study for this type of stuff

bright junco
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ohh, okayy. makes sense

mortal mango
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thanks alot for the help btw, really appreciate it

bright junco
mortal mango
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oh so u dont actually do the question

bright junco
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(that's when am lazy. which is 24/7)

mortal mango
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i see

bright junco
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if i feel productive i do the questions, then my hands hurt and i stop

mortal mango
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lmao

bright junco
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hey?

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do ya know Kinematics?

mortal mango
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nope

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am dumb

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dumb dumb

bright junco
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nah, ya aint dumb

mortal mango
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i am liek grade 5 math level

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we are currently learning factorisation

bright junco
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woah, then u wouldnt be in yr 8, would u? You're just the right level. Or maybe smart too

mortal mango
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soooo

bright junco
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factorisation is pretty easy, it must be a breeze for u

mortal mango
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ya im pretty sure other countries do it in like year 5 or 6

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idk why it is taking us so long

bright junco
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lemme show u smth

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gimme a sec

mortal mango
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In mathematics, Galois theory, originally introduced by Ɖvariste Galois, provides a connection between field theory and group theory. This connection, the fundamental theorem of Galois theory, allows reducing certain problems in field theory to group theory, which makes them simpler and easier to understand.
Galois introduced the subject for stu...

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what is this

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this is witchcraft

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i don't understand half the words

bright junco
mortal mango
#

oh

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oh wait that's wut we did

bright junco
mortal mango
#

huh

bright junco
mortal mango
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wth

bright junco
mortal mango
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why hcf and lcm for three straight years lmao

bright junco
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then yr 12 we stop.

bright junco
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in yr 8, do u see where i got 49?

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that's cause i was pissed off. It was the same thing over and over again. So i quit and i stopped doing yr 8. then i moved onto yr 9.

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And it was the same damn thing

mortal mango
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yeah

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LMAO

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what about the 33

mortal mango
bright junco
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all of them are incompleted tests

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i get annoyed easily when things are easy. and when they're hard i'll get pissed off too

mortal mango
#

makes sense

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yo someone else is here

bright junco
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yh, he's typin smth

mortal mango
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maybe he can confirm ur answer

bright junco
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he's smart

mortal mango
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i mean it looks right to me but idk

bright junco
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@boreal basalt is so darn smart

boreal basalt
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A remark on the problem: you assumed ABCD to be a square, which is fine and helpful to find the value of r
Nonetheless the setting is for any pair of positive side lengths for AB and BC of rectangle ABCD, and the value of r is solvable from that regardless

bright junco
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ya can ask him

bright junco
opal fernBOT
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@gray robin has given 1 rep to @boreal basalt

bright junco
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@mortal mango

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so then the answer's prolly 3

mortal mango
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so the square thing wasn't necessary but just made it easier

mortal mango
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love how he says "precisely"

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that

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s how u know he is smart

bright junco
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🤣

boreal basalt
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Though some would argue the area of a triangle, particularly that of a right-angled triangle, is simpler to get than the length of the hypotenuse, using Pythagoras's theorem

mortal mango
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i dont see how u would solve for the right angle triangle so imma go with pythagoras

boreal basalt
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Let's denote the length of AB as x metres

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Then since rectangle has area 1 sq. m, BC is 1/x metres long

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Then how long is DH, in terms of x?

mortal mango
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cd is also x so dh would be rx?

boreal basalt
mortal mango
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1/x + r(1/x)?

boreal basalt
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Yes, equivalent to (1 + r)/x upon factorization

mortal mango
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oh ye

boreal basalt
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This should tell us the area of the right-angled triangle DEH, which is?

mortal mango
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rx(1+x)

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i think

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i think that is wrong

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i got 1+rx * rx

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waot

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so then 1 + r^2 x^2

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?

boreal basalt
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Nah, the "/x" in (1+r)/x means division by x

mortal mango
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wait

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ooh

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hold on

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yeah

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i messed up

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1/2(rx * 1/x)

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is that it?

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r/2

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so the right angle triangle = r/2

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and the two triangles DEH and EAF have to = 12

boreal basalt
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Slowly

mortal mango
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is that right

boreal basalt
mortal mango
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OOH

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wait

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yea i messed it up

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i multiplied the base

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by AD

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but forgot to account for EA

boreal basalt
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And what do we get, with EA accounted for?

mortal mango
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so it would be 1/2(rx * 1/x + r(1/x))

boreal basalt
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Well, better check what we had for the "height" DE

mortal mango
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oh

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oh wait

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shoot

boreal basalt
#

Brackets are needed since multiplication precedes addition, but the addition is part of the formula for DE so it has to be done first

mortal mango
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wat

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wait

boreal basalt
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\begin{align*}
\text{Area of }\triangle DEH
&=\frac{1}{2}\times DE\times DH\
&=\frac{1}{2}\times\frac{1+r}{x}\times rx
\end{align*}

mortal mango
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what the

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ooh

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i see now that helps

flint belfryBOT
#

ā„afain

mortal mango
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so it would be 1/2 * (1+r)/x * rx

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oh

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yay

boreal basalt
#

Upon simplification, this area is $\frac{r(1+r)}{2}$

flint belfryBOT
#

ā„afain

mortal mango
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yeah

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and then

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can u solve for r from that?

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lemme see

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wait

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wat

bright junco
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what is the area given?

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(Just to help ya out)

mortal mango
#

uh

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that

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but now idk what to do with that

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do i do the same thing for triangle EAF?

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imma try that

bright junco
#

pretty sure youre supposed to have the value for the area, then u substitute so that u can find r.

bright junco
mortal mango
#

ooh

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trial and error

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?

bright junco
#

no, not trial and error

mortal mango
#

oh

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wat

bright junco
#

are u confused?

mortal mango
#

ya idk what to do with the equation now

bright junco
#

hmm

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am reading ur past messages

mortal mango
#

hold on

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if the triangles are equal

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wait

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nvm

bright junco
#

??

mortal mango
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we not using square strat

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lol

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nvm

bright junco
#

go on, what're ur thoughts?

bright junco
mortal mango
bright junco
mortal mango
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and then i got DEH/r - r = 1/2 but i dont think that does anythin

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wat

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no

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i messed it up

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oh

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no

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i didnt

bright junco
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ok, from what rafain told u, what do u understand?

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dont confuse urself. Just tell me what u know

mortal mango
#

bruh

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i was typing on laptop

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and then airplane mode randomly turned on

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ok im back on laptop

bright junco
#

alrighty

mortal mango
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AD = 1/x, DC = x
HD = rx
EA = r(1/x)
HED = 1/2(rx * (1/x + r * 1/x))

bright junco
#

ok, so to find the area of HED

mortal mango
bright junco
#

so if HED = EAF = FBG = GCH

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then, HED + EAF + FBG + GCH = area of EFGH - area of ABCD

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right?

mortal mango
#

ye

bright junco
#

so,

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HED + EAF + FBG + GCH = (25m^2) - (1m^2)

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HED + EAF + FBG + GCH = 24m^2

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since all the triangles are the same, we'll take all of them as x

boreal basalt
#

all the triangles are the same
Not really

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Each of them has the same area though, so the same reasoning afterwards applies

bright junco
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right,

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that's what i meant

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so then, x + x + x + x =24m^2

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4x = 24m^2

mortal mango
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oh so x is just 6

bright junco
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yup

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so the area is 6m^2

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then substitute that area, into the formula u obtained

mortal mango
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i think formula i obtained is wrong imma try real quick

bright junco
mortal mango
#

rx * (1/x + r(1/x))

bright junco
mortal mango
#

oh

bright junco
#

u got that?

mortal mango
#

i got that the first time with rafain's help

bright junco
#

that's the same as this equation but simplified

mortal mango
#

oh

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ooh

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oh ya

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so u just substitute and then

bright junco
#

yes. to make it easier to substitute. Try substituting now

bright junco
#

u get the answer

mortal mango
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wait wat but what do i substitute

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we got the answer to x

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but there is no x

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oh

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i substitute the unsimplified one

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and then simlify

bright junco
#

6m^2 = the simplified equation

mortal mango
#

wait no

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it gives the same thing

bright junco
bright junco
mortal mango
#

ooh

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because deh is x

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oh right

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i forgot deh was x

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that's why

bright junco
#

its aight, try substituting now

mortal mango
#

i got

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12 = r + r^2

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but

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idk wat to do with that now

bright junco
#

alr

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gimme a sec

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r would = 3. if u substituted

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am not sure how to exactky show that.

mortal mango
#

hol on a min it is quadratic

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r^2 + r - 12 = 0

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i think u do something with quadratic equation

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but idk that

bright junco
#

mhm

mortal mango
#

u get smth that multiply to ac and adds up to b?

bright junco
#

what i would do, is just assume that r = 3. Like, if r = 3
12 = 3 + 3^2

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that's how i would show my working out.

mortal mango
#

oh so just trial and error

bright junco
#

im not sure

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that's what id do

mortal mango
#

idk i think there is a way to solve this with qe but we havent learnt yet

boreal basalt
#

Two numbers which multiply to c/a and add up to -b/a

bright junco
#

ohh, like 12 - r = r^2

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like that?

mortal mango
bright junco
#

then u would find the perfect square under 12, which is 9

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then 12 -r = 9

mortal mango
#

lmao i got no idea

bright junco
#

so then 12 - 3 = 9. Then r = 3

mortal mango
#

havent learnt any of this

bright junco
#

inequalities and equalities?

mortal mango
#

ye i havent learnt

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oh

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wat

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that thing

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< >

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wait

bright junco
#

yea

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that thing

mortal mango
#

toh

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tho

bright junco
#

perfect square root

mortal mango
#

i didnt know u could just do that to find answer

bright junco
#

like 12 - r = r^2

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so if its subtract r, tehn r^2 should be a perfect square less then 12

mortal mango
#

wait

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oooh

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i see

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what is this method called?

bright junco
#

no idea

mortal mango
#

lmao

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trial and error should work at this point ig

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damn

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it's 1:40 now

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waking ip 6:30

bright junco
#

its called hash's idea

mortal mango
#

i should probably go to sleep

mortal mango
#

lol

bright junco
#

yh on ur exam paper just write that

mortal mango
#

anyways thanks a lot hash and rafain for the help i rlly appreciate it

bright junco
#

am kiddin, dont do that

mortal mango
#

nah

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ima do that

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if i end up using it

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will be funni

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chances are low that there is a very similar question to this tho

bright junco
#

sure, ur teacher will probably ask ya who on earth Hash is. Man am a famous mathmatician then

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šŸ˜Ž

mortal mango
bright junco
#

aight, sleep tight

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better do well on that exam tmrw

mortal mango
#

wow just spent over 2 hours on 1 question

mortal mango
opal fernBOT
#

@mortal mango has given 1 rep to @gray robin

mortal mango
#

wat is that

bright junco
#

as if i would know 🤣

mortal mango
#

was that automatic thing

bright junco
#

do i look like a walkin encyclopedia

mortal mango
bright junco
#

i have absolutely no idea what am saying or doing half the time

mortal mango
#

lmao

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only half?

bright junco
#

nvm all the time

mortal mango
#

aw i cant change my rep

opal fernBOT
#

Weekly Leaderboard
Guild: Mathematics (624314920158232616)
 Rank     Rep  Name
   #1       4  megaislive#0000
   #1       4  lorddarpinger#0000
   #1       4  anaguma1#0000
   #4       3  monkey111112121233_#0000
   #4       3  mimshell#0000
   #4       3  rafain#0000
   #4       3  omegabet_#0000
   #8       2  coolzly.#0000
   #8       2  khulpu#0000
   #8       2  hash_24#0000
mortal mango
#

ayy

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u got 2 now

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u are #1233040403779813408

#

what

#

#8

#

epic

#

rafain has 3

#

alr

#

i should sleep

#

cya

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thx for helping agian

bright junco
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cya, do well

bright junco
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tell me how ya do tmrw

mortal mango
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aight

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gonna be on 5 hrs of slepe

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but should be fine

whole ledgeBOT
mortal mango
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is that the cmd

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wait

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close

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how close

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??

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.close

solemn laurelBOT
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Unable to parse the channel name

mortal mango
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bruh wat

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got no clue

warm ledge
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r = 3?

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its easy but lengthy

warm ledge
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if you want i can give solution itss kinda messy

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just ping me

bright junco
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@warm ledge What's ur solution?

warm ledge
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wait i will send picture

bright junco
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alr

warm ledge
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i realised later i can just use x and y for the sides

bright junco
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im looking thro rn

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sure, this works aswell.

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honestly, depending on what works for u, either method 1, 2 or 3 (your method) could work. Either way you'll obtain the answer

warm ledge
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alright

bright junco
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nice job btw