#help grade 8 desperately
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i've done this so far but am 99% sure it is wrong:
also am currently last minute studying and am about to go to bed soon so may not reply if u reply after like an hour
help grade 8 desperately
yoo
it says it's a rectangle tho
or does that still work even tho it rectangle
it says ABCD is a rectangle
if they're expanded by the same ratio wouldn't that also make EFGH a rectangle?
even so, try substituting lxb=area of rectangle
so that means l x b=25m^2
there are no other combinations
factors of 25 are 1,5 and 25. So hence EFGH has to be a square.
ooohhh
i see i see
yeah that makes alot more sense now
hold on
so would r just be 5?
if sides of abcd are 1m
could there be decimals or smth?
let's try substituting that into the pythagoreas thereom
so hypotenuse= 5m
so if r=5 then AE=5m
that doesnt sound right.
instead, we can use the method of trial and error
take AE as x, and AF as y.
EF^2 = AE^2 + AF^2
hold on would r be 4 instead?
25= AE^2 +AF^2
yes, and AF = 3
but we can take AE as 3, and AF as 4
since AE is shorter than AF on the diagram
So answer could be r=3
how did u get this?
pythagoreas theorem
wait
ooh
AE^2 is a^2 in the theorem and AF^2 is b^2 in the theorem which is 25 or 5^2 (c^2 in the theorem)
is that it?
nonononoo
so a^2 is the hypotenuse of the triangle, so a^2 = EF
ill explain, hold on
hypotenuse is the longest side on the traingle
that's alright, feel free to ask me anything. It's best to clear ur doubts on the go. If not the whole thing will collapse
ooh ok
i tohught the hypotenuse was c
alright, would ya like me to start from the start?
okay, so let's get things straight
so area of EFGH is 25m^2. To find the sides we can substitute the values onto the area of a square formula. Area = Side x side.
so, 25m^2= 5m x 5m
hence, EF is 5m.
Ef = FG = HG = HE = 5m
so now, to find out the value of AE and AF we needa use the pythagoreas theorem
using trial and error we can assume that AE = 3m and AF = 4m
right?
because using pythagoreas theorem:
wait
sorry
what did we assume it was before?
its not Ef its AF
EF^2 = AF^2 + AE^2
ye
yeah
but i dont understand the trial and error part
what did we assume AF and AE were before?
we assumed it as 3 and 4
wait why tho
uh, okay the whole point of assuming is so that we can find out the values using pythagoreas theorem
yea
wanna dm me?
we can voice call ad it'll make it easier for u to understand
only if ya wanna?
ye
alr, moving on
so given in the question AE = r multiplied by AD, right?
and AE = 3m
so, 3m = r x AD
AD is most probably 1. and hence r = 3
i think. I hope it's right
who will check it then?
idk lmao
it's some math comp thing
and past paper
let me see if i can find answers to these papers
yea there's no solutions for it
ye i'll ask this one smart guy tmrw
wait, is this grade 8>
i dont remember grade 8 having questions like this..
darn i have bad memory
how old are u?
turning 13 this yr?
nah 14 this yr
no way, me too
yoo
but am not in grade 8 tho
yea, i might skip to grade 10 tho
tf
fingers crossed
are ya from the US?
or is it ur country is diff
australia
oh wait
ohh, am in the UK
i think that might be why you're in grade 9 or something
there are some 2011s in my class
im born on december 24
or uk school just better
if i was born on 2010 early before July. then i would be in yr 10
huuhhhh
but since am late december am in yr 9
uk school one year ahead of australia
bc we gotta study till yr 13
oh
which year do u gotta study till?
i thought uk education was similar to australia education
it's called the sixth form. yr12-13
sixth form?
yea lol
hold on so your education is a full year ahead of ours
Wales, Ireland and the whole of Uk follow em
nah, it's probably the same thing
when does ur school yr start? mine starts on september and ill be in yr 9 then
you think? š¤£
uh
well tbh idek
early next year
is all ik
which makes sense cuz new year so u go up a grade
yea, so you'll be in yr 9 on a february 2025. whereas ill be in yr 9 on a september 2024
practically just 4 months apart.
wait i thought u in grade 9 rn
wait that's where things get complicated
so, am not in England rn. am at mah gma's at another school
in which am in grade 9
it's complicated
so u grade 9 at one school and grade 8 at another
which is why i wanna be in grade 10 tis september
sorta, hmm.. its hard to say. cause im in yr 9 there aswell in a while.. so then
i thought u were grade 11 or smth because what is this stuff:
oh that's stuff that i know
i dont learn it in school. but i study outside of school
lol ok
oh ye the question i showed u was 1 out of 5 on a past paper that u have 2 hours to complete
how much time u have left? or did u complete the test?
oh no i'm taking it tmrw
was just doing last minute study
practise questions
cuz idk how ur meant to study for this type of stuff
ohh, okayy. makes sense
thanks alot for the help btw, really appreciate it
what i do, is i read thro the questions. Then i try to find out the method to complete the sums. Then i move on to the next questions.
oh so u dont actually do the question
(that's when am lazy. which is 24/7)
i see
if i feel productive i do the questions, then my hands hurt and i stop
lmao
nah, ya aint dumb
woah, then u wouldnt be in yr 8, would u? You're just the right level. Or maybe smart too
soooo
factorisation is pretty easy, it must be a breeze for u
ya im pretty sure other countries do it in like year 5 or 6
idk why it is taking us so long
In mathematics, Galois theory, originally introduced by Ćvariste Galois, provides a connection between field theory and group theory. This connection, the fundamental theorem of Galois theory, allows reducing certain problems in field theory to group theory, which makes them simpler and easier to understand.
Galois introduced the subject for stu...
what is this
this is witchcraft
i don't understand half the words
yr 8
yr 9
huh
wth
why hcf and lcm for three straight years lmao
then yr 12 we stop.
the numbers get bigger, that's the only difference
in yr 8, do u see where i got 49?
that's cause i was pissed off. It was the same thing over and over again. So i quit and i stopped doing yr 8. then i moved onto yr 9.
And it was the same damn thing
so school to ez for u basicall
all of them are incompleted tests
i get annoyed easily when things are easy. and when they're hard i'll get pissed off too
yh, he's typin smth
maybe he can confirm ur answer
he's smart
i mean it looks right to me but idk
@boreal basalt is so darn smart
A remark on the problem: you assumed ABCD to be a square, which is fine and helpful to find the value of r
Nonetheless the setting is for any pair of positive side lengths for AB and BC of rectangle ABCD, and the value of r is solvable from that regardless
ya can ask him
thanks, so then 3 would be reasonable, right?
@gray robin has given 1 rep to @boreal basalt
oh
so the square thing wasn't necessary but just made it easier
Precisely
š¤£
Though some would argue the area of a triangle, particularly that of a right-angled triangle, is simpler to get than the length of the hypotenuse, using Pythagoras's theorem
i dont see how u would solve for the right angle triangle so imma go with pythagoras
Let me try
Let's denote the length of AB as x metres
Then since rectangle has area 1 sq. m, BC is 1/x metres long
Then how long is DH, in terms of x?
cd is also x so dh would be rx?
Good, what about DE?
1/x + r(1/x)?
Yes, equivalent to (1 + r)/x upon factorization
oh ye
This should tell us the area of the right-angled triangle DEH, which is?
rx(1+x)
i think
i think that is wrong
i got 1+rx * rx
waot
so then 1 + r^2 x^2
?
Nah, the "/x" in (1+r)/x means division by x
wait
ooh
hold on
yeah
i messed up
1/2(rx * 1/x)
is that it?
r/2
so the right angle triangle = r/2
and the two triangles DEH and EAF have to = 12
Slowly
is that right
How did you arrive at this expression?
OOH
wait
yea i messed it up
i multiplied the base
by AD
but forgot to account for EA
And what do we get, with EA accounted for?
so it would be 1/2(rx * 1/x + r(1/x))
Well, better check what we had for the "height" DE
Brackets are needed since multiplication precedes addition, but the addition is part of the formula for DE so it has to be done first
\begin{align*}
\text{Area of }\triangle DEH
&=\frac{1}{2}\times DE\times DH\
&=\frac{1}{2}\times\frac{1+r}{x}\times rx
\end{align*}
āafain
Upon simplification, this area is $\frac{r(1+r)}{2}$
āafain
uh
that
but now idk what to do with that
do i do the same thing for triangle EAF?
imma try that
pretty sure youre supposed to have the value for the area, then u substitute so that u can find r.
this is the formula to help u obtain the area.
no, not trial and error
are u confused?
ya idk what to do with the equation now
??
go on, what're ur thoughts?
which triangle is this formula for?
DEH
ok, so the area of DEH = this
and then i got DEH/r - r = 1/2 but i dont think that does anythin
wat
no
i messed it up
oh
no
i didnt
ok, from what rafain told u, what do u understand?
dont confuse urself. Just tell me what u know
bruh
i was typing on laptop
and then airplane mode randomly turned on
ok im back on laptop
alrighty
AD = 1/x, DC = x
HD = rx
EA = r(1/x)
HED = 1/2(rx * (1/x + r * 1/x))
ok, so to find the area of HED
i added AD and EA, multiplied that by HD and divided in half
so if HED = EAF = FBG = GCH
then, HED + EAF + FBG + GCH = area of EFGH - area of ABCD
right?
ye
so,
HED + EAF + FBG + GCH = (25m^2) - (1m^2)
HED + EAF + FBG + GCH = 24m^2
since all the triangles are the same, we'll take all of them as x
all the triangles are the same
Not really
Each of them has the same area though, so the same reasoning afterwards applies
oh so x is just 6
i think formula i obtained is wrong imma try real quick
6m^2 = that
i tried doing it again and got that somehow tho
rx * (1/x + r(1/x))
yea, that's right. To simply we get this equation
oh
i got that the first time with rafain's help
that's the same as this equation but simplified
yes. to make it easier to substitute. Try substituting now
wait wat but what do i substitute
we got the answer to x
but there is no x
oh
i substitute the unsimplified one
and then simlify
6 m^2 = to that equation
what same thing?
its aight, try substituting now
alr
gimme a sec
r would = 3. if u substituted
am not sure how to exactky show that.
hol on a min it is quadratic
r^2 + r - 12 = 0
i think u do something with quadratic equation
but idk that
mhm
u get smth that multiply to ac and adds up to b?
what i would do, is just assume that r = 3. Like, if r = 3
12 = 3 + 3^2
that's how i would show my working out.
oh so just trial and error
idk i think there is a way to solve this with qe but we havent learnt yet
Two numbers which multiply to c/a and add up to -b/a
uhh
lmao i got no idea
so then 12 - 3 = 9. Then r = 3
havent learnt any of this
inequalities and equalities?
wut is this
toh
tho
perfect square root
i didnt know u could just do that to find answer
like 12 - r = r^2
so if its subtract r, tehn r^2 should be a perfect square less then 12
no idea
lmao
trial and error should work at this point ig
damn
it's 1:40 now
waking ip 6:30
its called hash's idea
i should probably go to sleep
yh on ur exam paper just write that
anyways thanks a lot hash and rafain for the help i rlly appreciate it
am kiddin, dont do that
fr
nah
ima do that
if i end up using it
will be funni
chances are low that there is a very similar question to this tho
sure, ur teacher will probably ask ya who on earth Hash is. Man am a famous mathmatician then
š
ya ill jsut say it's a mathematician
wow just spent over 2 hours on 1 question
thx
@mortal mango has given 1 rep to @gray robin
wat is that
as if i would know š¤£
was that automatic thing
do i look like a walkin encyclopedia
yes
i have absolutely no idea what am saying or doing half the time
nvm all the time
aw i cant change my rep
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ayy
u got 2 now
u are #1233040403779813408
what
#8
epic
rafain has 3
alr
i should sleep
cya
thx for helping agian
cya, do well
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yea i got it
if you want i can give solution itss kinda messy
just ping me
@warm ledge What's ur solution?
wait i will send picture
alr
im looking thro rn
sure, this works aswell.
honestly, depending on what works for u, either method 1, 2 or 3 (your method) could work. Either way you'll obtain the answer
alright
nice job btw