#simply and rationalise the denominator using conjugates
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gloomy token
Well, neither is correct.
tame sapphire
how so?
gloomy token
I don't quite understand what you did. You tried to rationalize the denominator, but didn't.
Let's try again. What is (-9 - √(2))(-9 + √(2))?
sage burrow
I don't quite understand what you did. You tried to rationalize the denominator,...
I think it's because he didn't apply a^2 - b^2 properly, he wrote the denominator as 81 - 9√2.
gloomy token
Recall that (a - b)(a + b) = a^2 - b^2.
gloomy token
I think it's because he didn't apply a^2 - b^2 properly, he wrote the denominato...
Ah, i see.
tame sapphire
I think it's because he didn't apply a^2 - b^2 properly, he wrote the denominato...
yea
sage burrow
The rest seems correct, just the formula was wrong.
You used a^2 + b^2 - 2ab I believe.
Which is for (a - b)^2.
gloomy token
As for the part of your question about 9√(2) and √(162): technically, both are correct, but it's nice when the number under the root is squarefree. So, I'd use 9√(2).
sage burrow
ive ended up with -81+9 root 2/ 79
Process?
gloomy token
ive ended up with -81+9 root 2/ 79
I assume you meant (-81 + 9√(2))/79. If so, that's good, as long as the solution is also correct.
tame sapphire
I assume you meant (-81 + 9√(2))/79. If so, that's good, as long as the solution...
yea, thats what i meant
gloomy token
yea, thats what i meant
Ok, nice!
tame sapphire
thank youu soo much