#Parametric equations
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how to go about
graphing this parametric equation
i know like
of the way is to
use this identity
$x = \sqrt{1-y^{2}}$
Gary
but why i can't use this
it gives me half circle
and not full
what is goin wrong
help!!
Desmos gives me a full circle with radius 1.
Are you saying x cannot be negative?
Also there will be a plus or minus outside the sqrt.
y = sin(t)
t = sin^-1(y)
x = cos(sin^-1(y))
Were you typing x = sqrt(1 - y^2) in desmos ๐?
$x =\pm\sqrt{1-y^{2}}$
Gary
right
๐
Try it now.
Lol.
its still a half circle
may be i have to put them
separately
ohhh it does
work
it does right
@full river
...because it's interpreting "plus/minus" as a constant coefficient.
broooo i didn't
know
๐ญ
lmao
thats why it didnt wirk this whole time
lmao
๐ฟ
thank u guys!!!
That's what it means when it gives you that slider. That slider is so you can select the value of the constant.
ahhhh
is there a way to make it don't take it as
variable
Take something like a.