#help with probability

45 messages · Page 1 of 1 (latest)

keen fox
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Consider the vowels "a,e,i,o,u" and the consonants "l,m,n,p,q,r"; How many distinct words, even meaningless, of 5 letters contain exactly 2 distinct consonants and 3 distinct vowels among them?

boreal fjordBOT
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signal wraith
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5c3x6c2x5!
( Selecting 3 vowels from 5 : 5c3
Similarly for consonants
6c2

Then 5! For no of ways we can rearrange those 5 selected letters)

I think that's the correct ans

keen fox
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so if i put 120 it's correct?

flat oar
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It should be C(5,2) * C(5,3). In these types of questions keep in mind that the number of possibilities is equal to C(Number of consonants, Number of constants used) * C(Number of vowels, number of vowels used).

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I used stuff like "number of constants" just for you to understand but this concept you can use in a lot of different questions.

keen fox
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so the answer is 100

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?

flat oar
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Should be.

keen fox
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i put in the system and it tells me that is not

signal wraith
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My ans is wrong?

keen fox
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nop

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but

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i don't know

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i put 100

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and it is wrong

flat oar
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Try 120.

signal wraith
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I think it's more than 120

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Lemme calc

keen fox
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ok

signal wraith
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54000

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Wtf

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That's way too much

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Lol

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My bad

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Did it wrong

keen fox
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120 didn't work

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may i do 54000?

signal wraith
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18000

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Try that

keen fox
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how can u do that

signal wraith
keen fox
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ok it was correct

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nice bro

signal wraith
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Do u know permutations and combinations?

keen fox
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yes but i started it yesterday for myself and i need it to get into university

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i am at the beginnings

signal wraith
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I used that to calculate it

keen fox
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i see, now i have the explanation from the system and it is like yours

signal wraith
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Alright, just thank me in #helper-nominations ig

keen fox
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you did C(6,2) for the consonants, multiplicated it to the vowels: C(5,3) and for pick up 5 letters u multiplicated all for 5! and so it was 18000

keen fox
keen fox
signal wraith
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It's fine