#I need to solve this and find exactly 2 solutions for a
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For the bottom one simplify for y in terms of x then substitute it into the first equation.
That doesn't work. Two equations, three variables. I'm thinking we don't have the full question.
What's the full question?
it's the full question
I can give you the right answer, but I don't know how to get it
I don't think it is.
it's not your typical algebra
I suspect that it's not algebra at all.
yes it is
damn that looks hard
So you're telling me there's nothing to the left, to the right, above, or below the frame of the image you sent that has anything whatsoever to do with the question?
It looks impossible is how it looks.
(-inf, -6/5) u (-6/5, -1/6] u {0} u [1/6, 6/5) u (6/5, inf)
here's the correct answer
it's a parametric equation
...no it's very much not?
yes it is
we clearly have y=+-ax
mane wtf
how?
That's wrong.
for what
for a
Not from the image you sent it's not.
that isn't exactly 2 solutions
@earnest badge read the question clearly first and send us the full question
it's the full problem
did they provide you with that exact picture?
You said that before and you were wrong.
yes
how am I wrong
it's will be on my final exam
Because what you're saying now is different from what you were saying before.
what did I say before?
And you said what you were saying before was the full question.
Just send us a picture of the original text of the question.
We need to know what the question says, not what you think the question says.
How are we supposed to find exactly two equations for "a"?
Sounds contradicting.
Find all values of "a", for each of which the system of equations has exactly two different solutions
this is exactly what the problem is saying
.
and this is the correct answer to this problem: (-inf, -6/5) u (-6/5, -1/6] u {0} u [1/6, 6/5) u (6/5, inf)
but I don't know how to get it
That's literally the third time you've said that. I have no reason to believe you. Why will you not just take a picture of the goddamn text of the goddamn question?
hahaha wow
I think what he means is that we have to find all possible $a\in\bR$ such that there exist 2 distinct pairs $(x,y)\in\bR^2$ which solve this idiotic system of equations
No Lifer #GTFOanemia
$4-y^2 = 4-a^2x^2$
No Lifer #GTFOanemia
$y^2=a^2x^2$
No Lifer #GTFOanemia
$x^2(1+5a^2)-x(12\pm10)=0$
$x(1+5a^2)-12\mp10=0$
No Lifer #GTFOanemia
$x = \frac{22}{1+5a^2},\frac2{1+5a^2}$
No Lifer #GTFOanemia
$y = \frac{484a^2}{25a^4+10a^2+1},\frac{4a^2}{25a^4+10a^2+1}$
No Lifer #GTFOanemia
what
yapperz
yeah question weird
anyways coffey I need help in real analysis (help-uni)
can you explain the solution please
I don't care what he means, I care what the question is.
It's the question, I put it in Google Translate for you
is English not your first language
No
f
brrrr I need to understand the goddamn question for that-
oh well
"Find all values of "a", for each of which the system of equations has exactly two different solutions"
this is the literal translation of the question, there's nothing more or less
"(-inf, -6/5) u (-6/5, -1/6] u {0} u [1/6, 6/5) u (6/5, inf)"
this is the correct answer for the problem
It's upsetting that you would assume I'm hiding the original problem from you. I provided you with the original text and even discovered a similar problem with a solution.
@grim wadi @deep perch
dude you clearly hid the question
you have to understand that we aren't obliged to help you, techie did it out of his own good will so you must cooperate!
how
the question is literally in the title, what difference will it make if I send the problem in my language? The google translate will give you the same result
"I need to solve this and find exactly 2 solutions for a" and "Find all value of a, for each of which the system of equations has exactly two different solution"
ARE NOT THE SAME
I literally said it right here, find the values of a
by that time techie had left
we thought you'd give us wrong information again and we'd end up jabbing at an erroneous question
no, Techie responded with "That's the third time you've said it"
I asked chat gpt if they're the same, "Yes, both statements are asking for the same thing – to find values of "a" for which a system of equations has exactly two different solutions."
ChatGPT is one of the most trash things humans created for math related things.
If you say "is 1 + 1 = 3" it will say yes.
ok it's not that idiotic lol but for proper problems it just dies
it is that idotic
it literally cant count bro
it literally cant even replace "." in a text with "->"s
its not, one means that we need to find 'exactly two value of a"
while the question really means find 'all the value of a' for which the system of eq has exactly 2 solutions
in first one 'a' is a varaible while in second one 'a' is a coeffeicnent
i think we can proceed this question
firstly find the domain of the y = +- ax due to the log fucntion
then if we see the graph of the ellipse in second equation
it passes through origin thefore the a for which it is tangent at the point that will be excluded
ig thats why + - 6/5 is excluded
and rest is excluded due to domain ig
if i am wrong please someone do correct me cz i am not 100% sure
um the solution already got posted lol
wait it did?
this
oh lol i didnt see lol
ok then make a help post
I can't help you in an existing help thread
ok yeah I've seen this reel lol
some dude gaslighted chatgpt