#Combinatorics Help
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So far what i did is substitute x5 for 0,1,2,3,4 and create new equations
which are
a + b + c + d = 12
a + b + c + d = 9
a + b + c + d = 6
a + b + c + d = 3
a + b + c + d = 0
where a is x1, b is x2 and so on
now the problem is getting the amount of probabilities for each
the last one is obviously 1
but then the rest is terrifying
for the penuultimate equation i got 19
bc
if all were 1 except for one value
itd be 6 ways
there are 12 ways to arrange 2 and 1
and 1 way to arrange 3
6 = 5 + 1
= 4 + 2
= 3 + 3
btw this is for middle equation
can be broken into 4 + 1 + 1, 3 + 2 + 1,
and 2 + 2
this can be broken down into
3 + 1 + 1 + 1, 2 + 2 + 1 + 1,
AND U HAVE TO FIND THE POSSIBILITIES OF ALL OF THEM
AND THEN REPEAT THIS AGAIN
FOR 2 MORE TIMES
BUT MORE COMPLEX 😭
thats 12 + 12 + 6
12 + 36
6 + 6?
i can't do this again and again 😭
wait is the answer 4^4?
love how im talking to myself
BRUH
DID ALL THAT FOR ME TO RELAIZE
BTW THE WAY I GOT IS
N^R
in order matter no matter repitiion no repittion table thingy
and nvm
you can start by considering the possibilities for x5 (0 to 4) and then just stars and bars the rest
@autumn wedge
sorry i thought someone already helped you from the message count lol
uhhhhh
.....
wha
uh
no its like uhh
i want 5 scoops of icecream and there are 3 flavours avaliable
how many different combinations of flavours can i get
and then you do
ooooo||
and then like uh
| separates the number of flavour of one kind
so oo|o|oo means tehres 2 of flavour 1, 1 of flavour 2, 2 of flavour 3
and gives you the number if ways you can do that
familiar or nah
ye
this right
yea
what i learnt was that was the sign for calculating stuff like that
didnt think to use it 😭
EVEN THOUGH I JUST LEARNT IT AND THAT WAS A PRAC OPROBLEM
im actually sped