#combinatorics

27 messages · Page 1 of 1 (latest)

cunning quartz
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I tried doing it the traditional way, but i dont think its the correct way to do it

brave fogBOT
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cunning quartz
fossil vault
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yes 2^10 = 1024

cunning quartz
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Do you have anything that uses up less time/effort?

fossil vault
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the hint I said lol

cunning quartz
fossil vault
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$\sum_{k=0}^{10}\binom{10}{k}=(1+1)^{10}$ by the binomial theorem

cerulean stormBOT
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Omegabet_

cunning quartz
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Ohhh right bc the products on the right are 1

fossil vault
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yes

cunning quartz
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Makes sense lol

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Thanks man

lavish spire
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you can have a nice combinatorial proof also :3

fossil vault
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duh

lavish spire
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yeah

fossil vault
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but also.. the question was resolved

lavish spire
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but like i just like nice combinatorial proof -w-

fossil vault
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ok

fossil vault
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count the number of subsets of {1,2,3,...,10}

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$\binom{10}{k}$ is the number of subsets with $k$ elements

cerulean stormBOT
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Omegabet_

cunning quartz
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+close