how do i calculate this

[karmic mauve]

i know how to calculate a right triangle but idk abt this one

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[brave pilot]

Suppose the given angles are α (larger one) and β (smaller one) and the distance between their vertices is d.
Try finding cot(β) - cot(α).

[lyric leaf]

Try calling the unmarked horizontal distance y.

[frozen venture]

try finding out the other 40° then maybe spliting that in half? then use ur soh cah toa tools to find out every length and angles? not sure, but when i did trig i would just figure out every angle and side😭

[lyric leaf]

"the other 40 degrees"?

[frozen venture]

Okay so i think this is what you do ti not give the answer but maybe help. first, you split where theres a 40° and so it becomes a right triangle. I know there is a way to get another length from angle and side. Once you get that length for the side you cut down, there could possibly be another length? then just doing that over and over til you get towards the x? tell me if im wrong because i do not want to spread misinfo😭 @lyric leaf

[karmic mauve]

and then?

[lyric leaf]

Well, what immediately comes to mind when you do that?

[karmic mauve]

you mean this side?

[frozen venture]

no theres the x

they need to find x pre sure

[karmic mauve]

what

can you show me in a picture plss

[candid goblet]

I think the middle is 400 since there is 2 equivalent Angles two lines should be the same Lenth

If what o Said is true, you can just use sine: sine(40)=x÷400=0,6427
Just Multiply 400 in both sides
X=257,11

[lyric leaf]

That's what I'm talking about, yes.

[karmic mauve]

i have the answer sheet and it says that x= 111,5 😭

[karmic mauve]

so i need to 400+y to get that whole side?

[storm thunder]

The triangle on top is an isosceles so the hypo on the small triangle is 400

And then apply toa cah soh