simple quadratic i just have 2 braincells

[bronze swallow]

y=3-(x-2)^2

[gilded obsidian]

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[bronze swallow]

how to factorise

i got -x^2-4x-1

but how is it +4x

[lone storm]

distribute the negative after you factor.

[bronze swallow]

i got told that in the (x-2)^2

when doing the a^2-2ab+b^2

b is still 2

the negative doesnt change it

it only changes the + or - 2ab

is that correct

so b is +2 in this equation

[lone storm]

I always do it piece wise

So you have 3 - (x-2)(x-2) . ok after that you would factor

doing it piecewise looks like this

xx + (-2)x + x(-2) + (-2)(-2)

which would give you

x^2-4x+4

following so far?

Then you put it back in your equation. Keep in mind that it is 3 - (factored equation)

so you have to distribute the - through the whole thing

so y = 3 - (x^2 - 4x +4)

@bronze swallow does this make sense?

[bronze swallow]

xx + -ab + -ab + bb

[lone storm]

yes. basically

[bronze swallow]

ok yes that makes sense

[lone storm]

then after you factor you distribute the negative so you would have:

3 + (-1)(x^2) + (-1)(-4x) + (-1)(4)

the negative sign is essentially a saying you have (3) + a (-1) times (your factor)