#complex inequality
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Focus on the fact that |z| is just the distance between point z and origin.
Thus, |z1| = |z1 - 0|.
Similarly for |z2|.
Finally, think of triangle inequality.
It seems C
No. That doesn't seem right.
you just calculate
$$ \sqrt{a^2+b^2} = \sqrt{c^2+d^2} + \sqrt{(a-c)^2 + (b-d)^2} $$
aL
and now conclude something
or you could note that
$$ |z| -|w|\leqslant |z-w| $$
aL
this holds always due to triangle inequality
so you just have to worry about the converse inequality
@devout stratus
and if it's none of these, think of counterexamples to each option that is not d)
Option a is correct