#calc ab question
67 messages · Page 1 of 1 (latest)
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You should split up the domain of integration into [-1, 2) and [2, 4] and consider them separately
The primitive function (or antiderivative) you wrote doesn't apply to [2, 4]
Why does it not apply may i ask
Try graphing f
is it because there is a hole in the graph
Jump I mean not hole
Bro the function is different in both interval
So spit it
Ok
wait would the antiderivative be (f(x))^2/2
I basically went back to where i started ??
well no not really
if you thought the whole thing was x^2/2
you miss out on the part thats just 3
What do you mean by just 3
LOL its ok
Wait so i dont do the x^2/2 so it would be like 3-(-1)^2/2
ok nvm im completely lost
so for example the integral between 2 to 4 would that become (3 - 3)
whats the antiderivative of 3
3x
So im not supposed to do the (f(x))^2/2 thing but instead plug in the numbers directly
Oops repliedto wrong thing
ok so ig the partim lost at is that i dont know how to integrate those parts
just treat it like two separate integrals
find their values
and add them together
simple!

if you wanna think about what youre doing graphically
youre just splitting this into two areas
and then adding them
i can see it visually but it doesnt help my math work calculation stuff
it sucks because most of the time i can visually see what the graph is supposed to look like but my answers usually come out wrong
okay lets get back to the inetgrals
what do you have so far
this is my logic at the moment
okay so
id like you to replace f(x) to what the actual equation is
thats a good way to start
and then take the antider
uh lets focus on just this part so it doesn’t take too much of ur time
Is this what you meant by replacing??