#Differential Equations

1 messages · Page 1 of 1 (latest)

peak citrus
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how would you get the general solution for this?

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serene mango
peak citrus
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but when i seperate them i end up having to integrate 1/x(x+1) dx

serene mango
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Yeah

peak citrus
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would i not end up diving by 0?

serene mango
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And?

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Assume x isn't 0 or -1

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There you go

peak citrus
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ik but i mean when i integrate

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if i add 1 to the power and then divide by the new power

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am i not diving by 0 there?

serene mango
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How do you integrate 1/x

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What's the primitive?

peak citrus
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ohh its lnx

serene mango
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And 1/(x+1)?

peak citrus
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ln x+1?

serene mango
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Yes

peak citrus
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oh ok that makes sense now thanks

serene mango
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So integral of 1/(x(x+1)) is some combination of those by partial fractions

peak citrus
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so would the general solution be y= x(x+1) + c

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if you integrate both sides then raise them to the power of e

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nvm would it be Ax(x+1) if A= e^c

serene mango
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,w integral of 1/(x(x+1))

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