solved

[pale raft]

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[halcyon night]

like why is it a=c·sin(A)/sin(C)

[static rose]

Sine theorem.

[halcyon night]

how do i apply it?

[static rose]

Suppose we have a triangle with sides a, b, c and angles A, B, C opposite of the respective sides. Then:
a/sin(A) = b/sin(B) = c/sin(C)

[halcyon night]

Could you explain it on real example?

[static rose]

Well, you don't use it for right triangles.

[halcyon night]

well then what do i use it for these ones? 😄

[static rose]

Here you go.

[static rose]

Well, too much data is given here. We don't need both angles. So, you can either use tangent or cotangent, depending on which angle you pick.

[halcyon night]

well can i still see example on this one?

with both tangent or contangent

[static rose]

Well, we have tan(A) = x/AC, cot(B) = x/AC. So, you can find x from either case.

[halcyon night]

alright. tysmmm

[eager jay]

@halcyon night has given 1 rep to @static rose

[static rose]

You're welcome!

[halcyon night]

solved

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