#Discriminant
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What have you tried?
i have no idea how to do it
...you said "discriminant" in the title.
thats the subtopic of it under the textbook
Okay, so what is the discriminant?
b^2-4ac
So in this case?
1-8
1^2-4(2)(1)
Still no. Answer the question I asked, please. What's a?
2
So what's c?
1
Where does this formula come from? What are a, b, and c here? Where do they come from, are they just completely random letters?
Okay, so then where's your variable b coming in?
parabola formula
wdym
use discriminant
What is the question asking?
Yes, hi, already helping.
find values for b if equation has real roots
What equation?
2x^2+x+b+1
So let's make a little change here.
Let's find the values of y if the equation 2x^2 + x + y + 1 = 0 has real solutions.
Literally all I did was rename our variable so that maybe it's less confusing.
So now, in our new equation, what's a?
2
And what's b?
1
And what's c?
1
...but then where's y?
Okay, let's maybe go back further to basics.
Looking at ax^2 + bx + c, a is everything that is multiplied by x^2, b is everything that is multiplied by x, and c is everything else.
So looking at 2x^2 + x + y + 1, a, b, and c are what?
2^2-4(1)(y+1)
Right.
๐
And when does the quadratic have real solutions?
when > 0
What about when it equals 0?
=0
What about when it's less than 0?
no
Why not?
because its not on x axis
I don't know if that's an answer.
because it doesnt intercept the x axis
What's "not on x axis"?
Okay, but why not?
Okay, look. Are you familiar with the quadratic formula?
-b+-sqrt b^2-4ac/2a
b^2-4ac
That's our discriminant, right?
yes
So then what happens when it's less than 0? When it's negative?
parabola concave down
...no.
Why not?
idk
Where did we just find the discriminant?
quadratic formula
Where in the quadratic formula?
the sqrt
And what happens when you take a square root of a negative number?
+-ans
...no.
math error ๐
You get an imaginary answer.
oh
That's why a negative discriminant gives no real solutions, because it gives complex solutions instead.
ok
A complex number, for the record, is just the sum of a real number and an imaginary number.
ok
So going way way back to the question, we want to determine when 1^2 - 4 * 2 * (y + 1) >= 0, right?
yes
Whoa, problem.
wait
That was a bunch of steps at once there.
1-8y+4
8+4y+4
This isn't showing me any work.
4x2+4xy+4x1
Stop guessing.
ok
Start with 1^2 - 4(2)(y + 1) >= 0.
And do one thing - exactly one - which you know you are allowed to do by the laws of algebra.
(2)(y+1)
And cite the law you're using.
So what does our inequality read now?
1-4(2y+2) >=0
Okay. Now do exactly one thing and cite the law of algebra you're using to justify it.
4(2y+2) = 8y+8 distributive law
So what does our inequality read now?
Wait.
Stop.
That's not even an inequality, it's just an expression.
So where's the minus come from?
I mean, either that or you would have 1^2 - (8y + 8) >= 0.
1-8y-8 >=0
Right.
-8y-7 >=0
-8+1=-7
8y became positive, why did that happen?
Okay.
-8y>=7
Right, adding 7 to both sides.
hm
yes
Is -2 > -1?
no
So what happened?
multipled by -1
And what does that do?
changes the equation
...well, it's not an equation, it's an inequality. Changes it how?
idk
Is -2 < -1?
No? So if it's not true that -2 < -1, and it's not true that -2 > -1, then is it true that -2 = -1?
wait
So what did we change?
the sign
What about the sign?
the way its facing
The direction.
greater to less than
yes
We changed the direction of inequality.
We have to do that when we have an inequality and we multiply by a negative or take the reciprocal.
So back here...
...no, we divide by -8. So we...?
change the direction
Right.
y<=7/-8
ah
so for example if it was 8y>=-7
and we divided both sides by 8
we would still change the direction of the sign
or no
No, because we're not multiplying both sides by a negative number.
Just a positive one.
ok so only if your multiplying by a negative you switch the direction
Or if they're on the same side of 0 and you take the reciprocal.
wdym by that
That is to say 0 < a < b implies 0 < 1/b < 1/a.
what
Look. 0 < 2 < 3, right?
yes
And 0 < 1/3 < 1/2?
yes
That's exactly what I'm talking about.