#help? algebra functions

24 messages · Page 1 of 1 (latest)

tight bane
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It says that the solution for a) is 5f(-x)+2f(x)=-2x^3-5x, f(x)=(2/3)x^3+(5/3)x.
b) Verify relation f(-x)=-f(x), any x E real
c) Observe that f(-n) + f(n) = 0, any n E {1,2,...,100}
Calculate S=f(0)=0

The subject has 5f(x)+2f(-x)=2x^3+5x. Why at a), they do 5f(-x)+2f(x)=-2x^3-5x?? how do they get to f(x)=(2/3)x^3+(5/3)x??
At b), i do not understand.
at c) is it Gauss formula??? why don't these solutions show the step by step?

Please if anyone has the patience to help me 😭

remote sandBOT
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tight bane
wide wren
exotic widgetBOT
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Omegabet_

wide wren
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solving the system for $f(x)$ concludes a

exotic widgetBOT
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Omegabet_

wide wren
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b just verify the definition of being an odd function

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c, by part b, f(-n)=-f(n), hence f(-n)+f(n)=0 for all n, so grouping the terms in this manner shows it's a sum of 0's

tight bane
tight bane
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And how do i verify it 😭

storm solstice
tight bane
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Or

wide wren
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$5f(-(-x))+2f(-x)=-2(-x)^3-5(-x)\to 5f(x)+2f(-x)=2x^3+5x$

exotic widgetBOT
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Omegabet_

wide wren
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so you get $\begin{cases}5f(x)+2f(-x)=2x^3+5x\
5f(-x)+2f(x)=-2x^3-5x\end{cases}$

exotic widgetBOT
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Omegabet_

wide wren
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so just solve the system for $f(x)$

exotic widgetBOT
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Omegabet_

wide wren