#negative exponents

43 messages · Page 1 of 1 (latest)

final sentinel
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how would I solve a sum like (-3x^2) ( -4x)^(-2)

fast onyxBOT
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lament hill
final sentinel
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but how do I solve it

lament hill
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Okay, so you know the rule $a^b * a^c = a^{b + c}$?

reef mapleBOT
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Techie Literate

final sentinel
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yes

lament hill
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So let's look at what happens when $c = -b$; $a^b * a^{-b} = a^{b + -b} = a^{b - b} = a^0 = 1$

reef mapleBOT
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Techie Literate

lament hill
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So $a^b * a^{-b} = 1$, which means $a^{-b} = \frac{1}{a^b}$ by simple algebra.

final sentinel
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yeah

reef mapleBOT
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Techie Literate

lament hill
final sentinel
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._.

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what

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what about the 4

lament hill
final sentinel
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and the negative

lament hill
final sentinel
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so the answer would be -16x ?

lament hill
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Or actually, that's just another exponent property; $(a * b)^c = a^c * b^c$

reef mapleBOT
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Techie Literate

lament hill
final sentinel
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._.

lament hill
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Look.

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First, what did the first property I proved show you?

final sentinel
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we add the exponents

lament hill
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...no.

final sentinel
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._.

lament hill
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$(-4x)^{-2} = \frac{1}{(-4x)^2}$

reef mapleBOT
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Techie Literate

final sentinel
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oh

lament hill
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That's what I proved to you.

final sentinel
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now I understand

lament hill
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Now, $-4x = -1 * 4 * x$, right?

reef mapleBOT
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Techie Literate

final sentinel
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then multiply the 1 with the previous (-3x^2) which would lead the ato -3x^2/16x^2 then -3/16 ?

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my internet cut off earlier

final sentinel
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I think I understand now though

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thanks

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*close

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+close