#negative exponents
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That's a product, not a sum.
but how do I solve it
Okay, so you know the rule $a^b * a^c = a^{b + c}$?
Techie Literate
yes
So let's look at what happens when $c = -b$; $a^b * a^{-b} = a^{b + -b} = a^{b - b} = a^0 = 1$
Techie Literate
So $a^b * a^{-b} = 1$, which means $a^{-b} = \frac{1}{a^b}$ by simple algebra.
yeah
Techie Literate
So just... do that.
(-4x)^(-2) equals what, according to what we just worked out?
and the negative
...the whole of -4x is our a in this context.
so the answer would be -16x ?
Or actually, that's just another exponent property; $(a * b)^c = a^c * b^c$
Techie Literate
No.
._.
we add the exponents
...no.
._.
$(-4x)^{-2} = \frac{1}{(-4x)^2}$
Techie Literate
oh
That's what I proved to you.
now I understand
Now, $-4x = -1 * 4 * x$, right?
Techie Literate