#Trig

35 messages · Page 1 of 1 (latest)

tame mural
queen sandalBOT
#
  1. Wait patiently for a helper to come along.
  2. Once someone helps you, say thank you and close the thread with:
+close
  1. Feel free to nominate the person for helper of the week in #helper-nominations
  2. Do not ping the mods, unless someone is breaking the rules.
  3. If you're happy with the help you got here, and the server overall, you can contribute financially as well:
long path
tame mural
#

sinx/cosx = 3/5

#

sinx = 3cosx/5

#

something like this

#

how would I solve this question?

rough lantern
# tame mural Help

Note:
sin(arctan(x)) = x/√(1 + x^2)
cos(arctan(x)) = 1/√(1 + x^2)
So, solve the trigonometric equation first, then use the formulas. You'll also need to remember some shift formulas for sine and cosine.

tranquil pelican
#

can something like this work here? if not then why

image.png
sleek sonnet
#

for this kind of exercices is very helpful to draw a triangle with what u know

#

since u know tan(a) is 3/5

#

it means the opposite side to an angle is 3 and the cont is 5

velvet locust
#

it always works for me

#

i mean cos(angle) and sin(angle) of course

desert canopy
#

wolfie is shitting on you in vc btw

wispy niche
# tame mural Help

Let $\sin\theta=3k$ and $\cos\theta=5k$ then $(3k)^2+(5k)^2=1$ thus we can find $k$ which gives us the desired.

mild mirageBOT
#

Romans 12:19

563022261809053696.png
wispy niche
desert canopy
#

"9+25=34????!"-wolfie2024

wispy niche
#

proof?

desert canopy
#

everytime i see a 9,25 or 34

#

ill remember it

#

sekai waffler

#

bro has it as his passive skill

#

(hes always yapping)

rough lantern
#

Well, as I said, my approach would be the following:
||tan(θ) = 3/5, π < θ < 3π/2 ⇒ θ = π + arctan(3/5)
sin(θ) = sin(π + arctan(3/5)) = -sin(arctan(3/5)) = -3/√(3^2 + 5^2) = -3/√(34)
cos(θ) = cos(π + arctan(3/5)) = -cos(arctan(3/5)) = -5/√(3^2 + 5^2) = -5/√(34)||

tame mural
tame mural
rough lantern
tame mural
tame mural
#

+close