#Area under curve
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what i dont understand is why didnt we consider the area b/w
x=0 and x=2
cuz thats not the area painted???
u dont even understand the problem. U dont have to find area between y=x, x=2 and y^2=8x
u have to find the area between y=x and y^2=8x between 2 and something (where they intersect)
and clearly ur intersection point isnt x=0
because the question doesnt want you to ... i guess?
Yeah, technically, that also counts. Maybe they didn't account for the fact that the left part is also contained inside the given lines.
the area wasnt painted in the question
i just gave you the diagram for better understanding
read the question i posted again ...
Maybe
i"ll have a look at other similiar questions if i find any
i"ll keep this post open tho
ohhh i see
well it’s the shaded idk i suppose the should say x=2 and to the right
but the diagram tells you what you need to find
probably someone not being paid enough made a description and did not look at it carefully
assuming it is what i colored, wouldnt if be integral from 2 to where they intersect of sqrt(8x)-x?
i know how to calculate that . I dont understand why they just want the area from 2 to sqrt 8x and not 0 to 2 .
im saying this again
There wasnt a shaded region in the question
this is the actual question
well its numerical , icant guess that always
oh
i guess u gotta do from 0 to 2 and from 2 to whatever
and see which one is bigger
and then do 3 times that
yea but that kind of wastes time i cant give on the question
its a question on a entrance paper
?
there is not waste of time since u only have to integrate once
lol
only the boundings change
i mean yeah , but still it would be better to get a concrete reason as to why only took it from x=2 to x= sqrt 8x
actually, cant u guess which area will be bigger by optimizing it? :D
would be fun
u could try
ah no, it wont work
nvm, just do it
i did solve from x=0 to x= 2 first and got the answer to be around 10 [3 alpha]
the area from x=2 to x=sqrt 8x was 112 [ 3 alpha]
so what you are saying is true
they indeed took the bigger area
then dont complain that much, is easy exercise
i could see which area is larger is i could draw the diagram with good scale
yeah it is easy
nah just solve both idk
wish it wasnt that ambigious
idk why would someone ask that
or any real scenario
so ask him/her, and tell me after
idk, maybe a robot trying to draw shapes on certain surface
and it wanna optimize the space so all the pieces fill?
the reason why im pushing on this is that , this is kind of a easy question so its free makrks . But it if its ambiogious like this , it only gets me a -1 . which affects my rank
plus i cant draw it to the exact scale , its a CBT test
ambiguos is this
this isnt