Derivative Triple Product Proof

[neat river]

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[indigo cliff]

Just set a new function

Let $j(x)=f(x)\cdot g(x)$

[golden badger]

TheVinkler

[indigo cliff]

And then you are calculating $\frac{d}{dx}j(x)h(x)$

[golden badger]

TheVinkler

[indigo cliff]

And now you can use the normal product rule

[raw wadi]

You can use logarithmic differentiation. You'll also see that this works for products of any length.

[hard maple]

damn really

oh yeah it's trivial

[raw wadi]

You can even do the same for Leibnitz's formula. You'll just get a multinomial expansion.