#Basic Integral Question Which Probably Won't Take Your 5 Seconds
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Simply this
Take u = x^2 + z^2.
Well I'm not really advanced in this topic what comes next
It becomes an elementary integral after that.
What does dx.x.Z become
Well, z is a constant, so we can just take it out of the integral.
If u = x^2 + z^2, what is du?
Akash!
Yes. So, xdx = (1/2)du.
The rest is easy.
Don't forget to change the limits of integration.
du/2(u)^3/2
use latex @dawn dragon
Thank you
Don't want to.
I'm having physics 2 class without having calculus 1
u may close using
+close
Yeah, unfortunately, that is quite common.
Physics lessons often use things from math that you haven't learned before.
I agree!
How come when you change variables d parts become something meaningful everytime?
That only happens when you perform a good substitution.
Yeah, I figured it was something like that.
which stream r u in
What do you mean by stream
Oh, interesting way to do it.
oh
How would you do it
Hm, one sec, let me try. Not sure if I remember enough how to do this.
Electric field magnitude is kq/d²
Have anyone of the two understood what charge, current, etc is
because a meme says one average it may take 10yrs
Charge is measured by the difference between protons and electrons on an atom
ok, but why charge? what significance it carries
If an atom doesn't have same amount of both, it means the atom is CHARGED
It's all about difference between energy
You want an electron, I want to give you an electron
Something interesting happens
Yea, but my mind goes to ionisation enthalpy
Well I do not have the enough knowledge on this topic to help you, sorry
Sorry for taking so long, haven't done this in a while. Like this.
I feel you it took me 50 mins
Well, it took us both a while, just for different reasons 😅
I didn't really understand the dEr part
Er will be zero because of symmetry.
Oh you mean Electric field on r axis
Yes.
can't say i understood this notation too (where -costeta and -sinteta is)
Sorry if I bore you with my ignorance
We have dE = (kq/|r|^2)e(dE), where e(dE) is its unit vector.
You can see from the picture that this unit vector is what's in the picture.
What is your major
Chemistry.
Wow good luck