simplifying trig expressions

[bitter rose]

ive been stuck on this for a bit and dont really know where to go

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[bitter rose]

i was thinking to start off with sinxcosx/(1-cosx)

or just sinx/(1/cosx -1)

[safe vault]

you could try multiplying top and bottom by the conjugate

[bitter rose]

okay

secx+1?

[safe vault]

yeah

it doesn't get that much simpler apparently

[bitter rose]

okay i got (sin(x)sec((x)+1)/tan^2(x)

since pythag indentity of sec^2(x) - 1 tan^2(x)

[safe vault]

yeah

no wait

both should be multiplied by sec(x) + 1

[bitter rose]

sorry yeah i meant + 1

on top

youre right

i wrote that wrong lol

[safe vault]

and make sure to get parentheses

it's sin multiplied by all of that

[bitter rose]

okay that equates to tanx + sinx up top

tanx + sinx / tan^2x