#algebra questions

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dreamy hemlock
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brazen pulsar
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  1. Collect similar terms.
  2. There are different ways to do this. The simplest is to find two side lengths, then multiply them.
  3. Domain is the set of x-values where the function is defined, range is the set of output values of the function.
  4. To find the asymptote, look at behaviour at infinity. If it behaves like a line, find its equation.
dreamy hemlock
brazen pulsar
dreamy hemlock
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i think the first one is + - + + - + -

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is that correct

dreamy hemlock
brazen pulsar
dreamy hemlock
dreamy hemlock
brazen pulsar
dreamy hemlock
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ohh alright

brazen pulsar
dreamy hemlock
brazen pulsar
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How are you getting minus in the second place?

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Ohh.

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Wait, hold on.

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I misread the problem, one sec.

dreamy hemlock
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alright

brazen pulsar
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What threw me off is that they started labelling signs from the second one, not the first one.

dreamy hemlock
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ohhhh no prob

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okay so for the next one

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are these right ?

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i left the last two blank bc im not sure

brazen pulsar
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Hm, nothing is correct.

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Can you explain your reasoning?

dreamy hemlock
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really?

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what about the asymptote? thats not correct either?

brazen pulsar
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No.

dreamy hemlock
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its not y = -3 right ?

brazen pulsar
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It is.

dreamy hemlock
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oh ?

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one sec

dreamy hemlock
brazen pulsar
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Better, but domain is still wrong.

dreamy hemlock
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is the range right

brazen pulsar
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Yes.

dreamy hemlock
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(-∞, ∞)

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is that the domain?

brazen pulsar
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Yeah, that's correct.

dreamy hemlock
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yayy okay

brazen pulsar
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Now, the limits at infinities.

dreamy hemlock
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and how do i figure out the other questions

brazen pulsar
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To do that, look at what the value of the function becomes for x -> +∞ and for x -> -∞.

dreamy hemlock
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∞
-∞

brazen pulsar
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Well, +∞ is correct for x -> -∞.

dreamy hemlock
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-∞ is wrong for x -> ∞?

brazen pulsar
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It is wrong, yes.

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We have an asymotote y = -3 for x -> +∞.

dreamy hemlock
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-3 is for x -> ∞?

brazen pulsar
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Yes.

dreamy hemlock
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ohhh okay

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and this is my last question

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ive answered the first

brazen pulsar
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Oh man, these questions...

dreamy hemlock
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  1. This expression is a prime quadratic, meaning it cannot be factored further as it does not have any factors other than 1 and itself.
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and its prime

brazen pulsar
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I kinda hate how this is taught, to be honest.

dreamy hemlock
brazen pulsar
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Like, I don't see a point in learning 9001 different ways of solving quadratics when just three are enough.

dreamy hemlock
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right

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it confuses me

brazen pulsar
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Well, let's try...

dreamy hemlock
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yup

brazen pulsar
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Well, (4) contains square root as the leading and constant coefficients.

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There is an option like that.

dreamy hemlock
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  1. This expression starts and ends with perfect squares, and the middle term is twice the product of the square roots of the first and last terms.
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is that right ?

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perfect square trinomial

brazen pulsar
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So far, we got this.

image.png
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What about (5)?

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Ohh, wait.

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There are two groups of answers...

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Aw man.

dreamy hemlock
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Yes

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for 4 its perfect square trinomial and This expression starts and ends with perfect squares, and the middle term is twice the product of the square roots of the first and last terms.

brazen pulsar
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Is this what they mean us to do?

image.png
dreamy hemlock
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and for one its prime and This expression is a prime quadratic, meaning it cannot be factored further as it does not have any factors other than 1 and itself.

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yes

brazen pulsar
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Oh, alright.

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Well, anyway. What about (5)?

dreamy hemlock
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is 5 Difference of Two Squares ?

brazen pulsar
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Yes. And?

dreamy hemlock
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this expression contains two perfect squares and has a subraction sign in the middle

brazen pulsar
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Let's look at (3).

dreamy hemlock
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im not so sure

brazen pulsar
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Well, I can notice that we can factor 2 out.

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Other than that, it's irreducible.

dreamy hemlock
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is it the last one?

brazen pulsar
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No, the third row.

dreamy hemlock
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no the last answer choice

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the one on the bottom

brazen pulsar
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Well, that won't work for (3), as it does at least have a common factor.

dreamy hemlock
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greatest common factor only?

brazen pulsar
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Yes. And the one in the third row. So, this.

image.png
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Only (2) and (6) are left.

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To be honest, it's easier to do that by exclusion, since I have no idea what they are talking about in the second-to-last statement...

dreamy hemlock
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wait also i have a question

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so the type of quadratic that would be the blue line right ?

brazen pulsar
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Yes.

dreamy hemlock
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okay so

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is 2 in the 6th row?

dreamy hemlock
dreamy hemlock
brazen pulsar
dreamy hemlock
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oh

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so 2 is grouping and the one on the 6th row

brazen pulsar
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Probably? As I said, no idea what's happening on the sixth row.

dreamy hemlock
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yup i got it right

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thank you so much sir

brazen pulsar
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Great! You're welcome.

wary aspenBOT
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@dreamy hemlock

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sick roost
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