#indefinite integral
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hollow sand
u = sqrt(x)
sturdy plume
u = sqrt(x)
When I do the u sub I then get 1/2(2) ∫ 1/3+u^2 du
is that right so far? If so I’m stuck here
hollow sand
When I do the u sub I then get 1/2(2) ∫ 1/3+u^2 du
is that right so far? If so ...
yes
then use trig sub
sturdy plume
then use trig sub
I don’t know how
hollow sand
I don’t know how
you know trig sub?
sturdy plume
you know trig sub?
yes but I don’t see why I need it here
hollow sand
yes but I don’t see why I need it here
cuz of the 3+u²
boreal flicker
cant u do partial fractions on that one?
hollow sand
sub in u = sqrt(3)tan(v)
hollow sand
cant u do partial fractions on that one?
how? cuz there's the square root
boreal flicker
idk, A/sqrt + B/3+x woldnt work? i may have spoken too fast
hollow sand
idk, A/sqrt + B/3+x woldnt work? i may have spoken too fast
I don't think it would
sturdy plume
I give up