#Indicies and Surds
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$(n^2-5n+5)^{n^2-11n+30}=(n^2-5n+5)^{0}$\
Therefore, $n^2-5n+5=1$ and $n^2-11n+30=0$ give the only solutions.
Romans 12:19
However, make sure to test if the roots of $n^2-11n+30=0$ do not satisfy $n^2-5n+5=0$ to avoid a $0^0$ form.
Romans 12:19
send awith full working out
?
i want full working out
No.
I'm going to give you hints, help you solve it.
no
this other math server has got to stop spitting out answers for kids to just copy
what